Cannot convert value of type '[String]?' to expected argument type 'String'

Question

What I want to do is set the image of firstCard to be equal to the image file with the name corresponding to firstCardString.

For instance, in the case below, the code could be setting self.firstCard.image to show the image named "card1" if it randomly picks it (I've clipped the rest of the array for brevity, the full thing contains 52 objects).

var deckArray = [
        "card1": ["Bear","Ball"],
        "card2": ["Bear","Ball"],
        "card3": ["Bear","Ball"],
        "card4": ["Bear","Ball"],
        "card5": ["Bear","Ball"],
        "card6": ["Bear","Ball"],
        "card7": ["Bear","Ball"],
]

    let firstRandomNumber = Int(arc4random_uniform(52))+1
    let firstCardString = deckArray["card\(firstRandomNumber)"]
    self.firstCard.image = UIImage(named: firstCardString)

Instead, I'm getting the following error:

Cannot convert value of type '[String]?' to expected argument type 'String'

I'm not entirely sure what this error message means, what is [String]??

andyvn22 · Accepted Answer · 2015-10-26 22:32:42Z

7

[] is an array, and ? is an optional. Your firstCardString is not a string at all, but an optional array of strings. You've read the deckArray dictionary's value for that card, you see, and so your firstCardString actually looks something like this: Optional(["Bear", "Ball"]). I think you meant:

self.firstCard.image = UIImage(named: "card\(firstRandomNumber)")

This will set the image based on strings like "card1" or "card4". I assume you'll use your dictionary for something else, later. When you do, be sure to unwrap the optional value it returns:

if let cardArray = deckArray["card\(firstRandomNumber)"] {
    //do something with bears and balls
}

Alternatively, consider making deckArray an array (which will make the name more reasonable), rather than a dictionary. Then you won't have to deal with optionals and will be able to access items as follows:

let cardArray = deckArray[firstRandomNumber]
//do something with bears and balls

edited Oct 26, 2015 at 22:32

answered Oct 26, 2015 at 22:27

andyvn22

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3 Comments

Andrew Over a year ago

But if I use self.firstCard.image = UIImage(named: "card\(firstRandomNumber)"), won't that attempt to set firstCard to an image name which is just a random number between 1 and 52, rather than setting it to the key ("card4") that corresponds to the index with that number?

andyvn22 Over a year ago

The image name will be "card1" or "card3" or "card5". See the word "card" there in the name? It's followed by \(firstRandomNumber), which will insert the number right after the word "card".

Xcodian Solangi Over a year ago

@andyvn22 please answer the same related question here stackoverflow.com/questions/42733225/…

Daniel · Accepted Answer · 2015-10-26 22:55:10Z

3

Your deckArray is a Dictionary, and your firstCardString is an Array.

String = String

[String] = Array of strings.

answered Oct 26, 2015 at 22:55

Daniel

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1 Comment

Xcodian Solangi Over a year ago

please answer the similar related question here stackoverflow.com/questions/42733225/…

f1yingbanana · Accepted Answer · 2015-10-26 22:27:40Z

0

It seems like deckArray is in fact, a dictionary of arrays of strings. Therefore if firstRandomNumber = 1, deckArray["card\(firstRandomNumber)"] will return ["Bear","Ball"]. That is definitely not a string!

answered Oct 26, 2015 at 22:27

f1yingbanana

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1 Comment

Xcodian Solangi Over a year ago

please answer the similar related question here stackoverflow.com/questions/42733225/…

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