char *test = "hello";
test = change_test("world");
printf("%s",test);
char* change_test(char *n){
printf("change: %s",n);
return n;
}
im trying to pass a 'string' back to a char pointer using a function but get the following error:
assignment makes pointer from integer without a cast
what am i doing wrong?
A function used without forward declaration will be considered having signature int (...). You should either forward-declare it:
char* change_test(char*);
...
char* test = "hello";
// etc.
or just move the definition change_test before where you call it.
printf() prints the text to the console but does not change n. Use this code instead:
char *change_test(char *n) {
char *result = new char[256];
sprintf(result, "change: %s", n);
return result;
}
// Do not forget to call delete[] on the value returned from change_test
Also add the declaration of change_test() before calling it:
char *change_test(char *n);
new, try malloc()/calloc() instead.You're converting an integer to a pointer somewhere. Your code is incomplete, but at a guess I'd say it's that you're not defining change_test() before you use it, so the C compiler guesses at its type (and assumes it returns an integer.) Declare change_test() before calling it, like so:
char *change_test(char *n);
thanks a bunch guys! didnt think i would have this problem solved by lunch. here is the final test class
/* standard libraries */
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char* change_test(char*);
int main(){
char *test = "hello";
test = change_test("world");
printf("%s",test);
return (EXIT_SUCCESS);
}
char* change_test(char *n){
return n;
}