Create regular expression using android pattern

Question

I have a sample message . I need to create a regular expression to validate using android pattern.

sample message : ERR|any digit|any digit;

checking validation:

1.Starting fixed characters :ERR

separator character :|
digit after | character
Message termination ;

I have tried like this way:^{ERR}+{|}+\d+{|}+\d+{;}$

Am I right? Please help to solve my problem.

you should add regex tag to your question you might recieve help — Bhargav
– Bhargav, Commented Nov 17, 2015 at 6:57

elimirks · Accepted Answer · 2015-11-17 08:01:15Z

1

The corrected regex you gave would be ^(ERR)+(\\|)+\\d+(\\|)+\\d+;$. Brackets are used for grouping, not braces. Also, in regex, + is used to represent "one or more of the previous expression". So writing (ERR)+ means "one or more of the string 'ERR'", so strings like "ERRERR|123|456;" would be matched (same thing goes for the pipe characters) - this is not what you are trying to do, I assume.

Having said that, try this: "^ERR\\|\\d+\\|\\d+;$"

edited Nov 17, 2015 at 8:01

answered Nov 17, 2015 at 7:28

elimirks

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2 Comments

Giuseppe Ricupero Over a year ago

The elimirks answer is formally correct (based on what we know), only needs some double escaping: Pattern p = Pattern.compile("^ERR\\|\\d+\\|\\d+;$");

elimirks Over a year ago

@GsusRecovery Thanks for the correction - I updated it accordingly

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