Im getting the error:
>>> sum_digits(123)
Traceback (most recent call last):
File "<pyshell#16>", line 1, in <module>
sum_digits(123)
File "D:/Python/Final/#4.py", line 4, in sum_digits
for i in n:
TypeError: 'int' object is not iterable
>>>
def sum_digits(n):
s = 0
for i in n:
s += n
return s
You need to convert the number to str (not int) and iterate it:
def sum_digits(n):
s = 0
for i in str(n):
s += int(i)
return s
usage:
>>> sum_digits(123)
6
Using sum and generator expression:
def sum_digits(n):
return sum(int(i) for i in str(n))
# OR return sum(map(int, str(n)))
The problem here is that your are passing an int to your function, which you cannot iterate over.
I suggest the solution
>>> n = 123
>>> sum(int(x) for x in str(n))
6
If you want i to range over the digits of n, you'd need something like:
for i in [int(x) for x in str(n)]:
Or, you could just pass "123" instead of 123 to sum_digits, which the title of your post suggests is what you actually mean to do. Of course, then you'd need to convert each character to its numeric value.
You cannot iterate over an int but you can still do it without casting to str:
def sum_digits(n):
n, i = divmod(n, 10)
while n:
n, r = divmod(n, 10)
i += r
return i
Demo:
In [2]: sum_digits(123456789)
Out[2]: 45
In [3]: sum_digits(123)
Out[3]: 6
In [4]: sum_digits(100)
Out[4]: 1
It does not make much sense to convert from int to str then back to int again.
for i in int(n),for i in n