How to replace urls using regex php

Question

i have a text file in which i have many urls like this http://96.156.138.108/i/01/00382/gbixtksl4n0p0000.jpg#xywh=0,0,108,60

i want to change all urls with my urls like this http://testing.to/testing/vtt/vt1.vtt#xywh=0,0,108,60

i am using this regex

$result = preg_replace('"\b(https?://\S+)"', 'http://testing.to/testing/vtt/vt1.vtt', $result);

but its not working good its change whole url

from this http://96.156.138.108/i/01/00382/gbixtksl4n0p0000.jpg#xywh=0,0,108,60

to this http://testing.to/testing/vtt/vt1.vtt

i want to change only url except #xywh==0,0,108,60 like this

http://testing.to/testing/vtt/vt1.vtt#xywh==0,0,108,60

falsetru · Accepted Answer · 2015-12-17 08:51:43Z

2

You can use [^\s#] instead of \S to match only non-spaces, non-# characters:

$result = preg_replace(
    '"\bhttps?://[^\s#]+"',
    'http://testing.to/testing/vtt/vt1.vtt',
    $result
);

answered Dec 17, 2015 at 8:51

falsetru

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2 Comments

Zeal Sol Over a year ago

i also want to get old url http://96.156.138.108/i/01/00382/gbixtksl4n0p0000.jpg from file into my variable what should i do

falsetru Over a year ago

@ZealSol, Use the same pattern with preg_match: preg_match('"\bhttps?://[^\s#]+"', $result, $matches); print_r($matches);

Alex Andrei · Accepted Answer · 2015-12-17 09:11:30Z

1

Although preg_replace is good and all, there is a built in function for parsing urls,
namely parse_url

$url = 'http://96.156.138.108/i/01/00382/gbixtksl4n0p0000.jpg#xywh=0,0,108,60';

$components = parse_url($url);

print_r($components);

$fixed = 'http://testing.to/testing/vtt/vt1.vtt#' . $components['fragment'];

print $fixed . PHP_EOL;

Will output

Array
(
    [scheme] => http
    [host] => 96.156.138.108
    [path] => /i/01/00382/gbixtksl4n0p0000.jpg
    [fragment] => xywh=0,0,108,60
)

http://testing.to/testing/vtt/vt1.vtt#xywh=0,0,108,60

answered Dec 17, 2015 at 9:11

Alex Andrei

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Comments

Yash · Accepted Answer · 2015-12-17 09:11:41Z

1

Try This:

$sourcestring="http://96.156.138.108/i/01/00382/gbixtksl4n0p0000.jpg#xywh=0,0,108,60";
echo preg_replace('/https?:\/\/.*?#/is','http://testing.to/testing/vtt/vt1.vtt#',$sourcestring);

edited Dec 17, 2015 at 9:11

answered Dec 17, 2015 at 8:57

Yash

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2 Comments

falsetru Over a year ago

http? should be https?.

Yash Over a year ago

Correct it should be https? ... Thanks

monirz · Accepted Answer · 2015-12-17 08:53:39Z

0

It could be done with simple explode() function

$url = "http://96.156.138.108/i/01/00382/gbixtksl4n0p0000.jpg#xywh=0,0,108,60";

$urlParts = explode("=", $url);

$newUrl = "http://testing.to/testing/vtt/vt1.vtt#xywh=";

$newUrl += $urlParts[1];

answered Dec 17, 2015 at 8:53

monirz

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1 Comment

falsetru Over a year ago

Considering xywh could be changed: $urlParts = explode("#", $url); $newUrl = "http://testing.to/testing/vtt/vt1.vtt#";

Huzaib Shafi · Accepted Answer · 2015-12-17 08:57:46Z

0

$re = "/(.*)#(.*)/"; 
$str = "http://96.156.138.108/i/01/00382/gbixtksl4n0p0000.jpg#xywh=0,0,108,60"; 
$subst = "http://testing.to/testing/vtt/vt1.vtt#$2"; 

$result = preg_replace($re, $subst, $str);

OR

$re = "/(http?:.*)#(.*)/"; 
$str = "http://96.156.138.108/i/01/00382/gbixtksl4n0p0000.jpg#xywh=0,0,108,60"; 
$subst = "http://testing.to/testing/vtt/vt1.vtt#$2"; 

$result = preg_replace($re, $subst, $str);

answered Dec 17, 2015 at 8:57

Huzaib Shafi

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