How to call javascript function from php echo?

Question

Hi all i am trying to call javascript function called loadvideo from php echo and i keep getting errors. I tried two methods

1)first Method i get this error:

Parse error: syntax error, unexpected '<' in

echo ("<td><a href=\"javascript:loadVideo('$URL\','image1.jpg')">$item['name']</a> <br/></td>\n");

2)second method i get this error:

Parse error: syntax error, unexpected '' (T_ENCAPSED_AND_WHITESPACE), expecting identifier (T_STRING) or variable (T_VARIABLE) or number (T_NUM_STRING)

echo ("<td><a onClick='loadVideo(" . $URL . ");'>$item['name']</a><br/></td>\n");

could any one show me how to fix this ?Thanks in advance.

javascript function to call:

<script>
  function loadVideo(myFile,myImage) { 
    jwplayer().load([{
      file: myFile,
      image: myImage
    }]);
    jwplayer().play();
  };
</script>

What is it displaying in the HTML? See view source and tell how it is generating. — Praveen Kumar Purushothaman
– Praveen Kumar Purushothaman, Commented Dec 20, 2015 at 19:35
Thanks for replies. I get those errors i can't click nothing! — user1788736
– user1788736, Commented Dec 20, 2015 at 19:40

Franco · Accepted Answer · 2015-12-20 19:37:58Z

1

Try this one:

echo ("<td><a href=\"javascript:loadVideo('$URL\','image1.jpg')\">".$item['name']."</a> <br/></td>\n");

answered Dec 20, 2015 at 19:37

Franco

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Comments

Praveen Kumar Purushothaman · Accepted Answer · 2015-12-20 19:36:13Z

0

Change the second one to:

echo ("<td><a onClick='loadVideo(\"" . $URL . "\");'>$item['name']</a><br/></td>\n");

answered Dec 20, 2015 at 19:36

Praveen Kumar Purushothaman

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Comments

Bhavin Solanki · Accepted Answer · 2015-12-20 19:38:31Z

0

I have check second method. There you missing quote of php variable.

Here is updated method

First method updated::

echo ("<td><a href=\"javascript:loadVideo('$URL','image1.jpg')\">$item['name']</a> <br/></td>\n");

Second method :

    echo ("<td><a onClick='loadVideo(" . $URL . ");'>".$item['name']."</a><br/></td>\n");

This will work.

answered Dec 20, 2015 at 19:38

Bhavin Solanki

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Dr M L M J · Accepted Answer · 2015-12-20 19:41:37Z

0

change First one with

echo ("<td><a href=\"javascript:loadVideo(".$URL.",'image1.jpg')\">".$item['name']."</a> <br/></td>\n");

answered Dec 20, 2015 at 19:41

Dr M L M J

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Comments

Rajdeep Paul · Accepted Answer · 2015-12-20 19:53:19Z

0

There are small bugs in your code.

Change the first one like this:

echo "<td><a href=\"javascript:loadVideo('$URL\','image1.jpg')\">{$item['name']}</a> <br/></td>\n";

And the second one like this:

echo "<td><a onClick='loadVideo(" . $URL . ");'>{$item['name']}</a><br/></td>\n";

answered Dec 20, 2015 at 19:53

Rajdeep Paul

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jherrieven · Accepted Answer · 2015-12-20 20:50:40Z

0

First approach:

echo ("<td><a href=\"javascript:loadVideo('".$URL."','image1.jpg');\">".$item['name']."</a> <br/></td>\n");

Second approach:

echo ("<td><a onclick=\"loadVideo('".$URL."','image1.jpg');\">".$item['name']."</a> <br/></td>\n");

answered Dec 20, 2015 at 20:50

jherrieven

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