Adding custom parameter in an url on Python 3.5

Question

connection = urllib.request.urlopen("http://www.wdyl.com/profanity?q=" + text_to_check)

I don't know why but the code above is not working in python 3.5 and after several hours of searching i yet to find any answer for that. What i want to do is adding text_to_check string in the end of url

The error i'm receiving is:

raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 400: Bad Request

"is not working" is about the most useless definition of a problem. Please explain what you get exactly. — bruno desthuilliers
– bruno desthuilliers, Commented Jan 7, 2016 at 12:34
i edited my question. If i remove + text_to_check part, the url alone is working without any error or issue — ggnoredo
– ggnoredo, Commented Jan 7, 2016 at 12:36
it's full of text from a .txt file. I can print it there is no issue there. — ggnoredo
– ggnoredo, Commented Jan 7, 2016 at 12:38

eumiro · Accepted Answer · 2016-01-07 12:40:58Z

1

The problem is your text_to_check.

Try this:

query = urllib.parse.urlencode({'q': text_to_check})
urllib.request.urlopen("http://www.wdyl.com/profanity?" + query)

and print the query variable to see what has to happen with your "full of text from a .txt file" in order to work correctly as a URL.

answered Jan 7, 2016 at 12:40

eumiro

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2 Comments

ggnoredo Over a year ago

it worked thank you! but i did not understand the code. I searched a lot but none of the solutions provided is similar to this approach

eumiro Over a year ago

@fuzunspm - you can also have a look at requests, which may shorten the number of methods you will need: docs.python-requests.org/en/latest/user/quickstart/…

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