Access PHP array objects

Question

I have the following array output:

Array ( [0] => stdClass Object ( [name] => asdasd [email] => [email protected] [message] => asdasd ) )

Which is given by the following code:

if(isset($_POST['emailContent'])){
        $mail = new PHPMailer;
        $emailContent = $_POST['emailContent'];
        $emailContent = json_decode($emailContent);

        print_r($emailContent);
    }

I need to access the actual object and get the info from name, email and message.

How can I do this?

I have tried

$name = $emailContent[name];
$name = $emailContent['name'];

but no luck so far. Any ideas what I might be doing wrong?

try $emailContent[0]->name

RomanPerekhrest
– RomanPerekhrest

2016-01-14 07:11:52 +00:00
Commented Jan 14, 2016 at 7:11 — RomanPerekhrest
– RomanPerekhrest, Commented Jan 14, 2016 at 7:11
tried $emailContent.name; or $emailContent->name;?

Atu
– Atu

2016-01-14 07:11:59 +00:00
Commented Jan 14, 2016 at 7:11 — Atu
– Atu, Commented Jan 14, 2016 at 7:11

Sebastian Brosch · Accepted Answer · 2016-01-14 07:12:02Z

2

Try the following solution:

$name = $emailContent[0]->name;
$email = $emailContent[0]->email;
$message = $emailContent[0]->message;

answered Jan 14, 2016 at 7:12

Sebastian Brosch

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2 Comments

CodeTrooper Over a year ago

This does it. Not sure how this happened.. I've never worked with arrays like this before. Is it because I used JSON_DECODE?

Jigar Over a year ago

@codeninja: if you need array from json_decode, use second parameter. like json_decode($emailContent, true).

patilvikasj · Accepted Answer · 2016-01-14 07:47:22Z

1

Your Object array has a value on 0th index so you need to access it by specifying index as , $emailContent[0]->name; to get name value here 0 is index . Similar for email and message as , $emailContent[0]->email; $emailContent[0]->message;

answered Jan 14, 2016 at 7:47

patilvikasj

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Comments

Prafulla Kumar Sahu · Accepted Answer · 2016-01-14 07:12:04Z

0

if the array you have var_dumped is $emailContent you can retrieve the data as below :-

$emailContent[0]->name
$emailContent[0]->email
$emailContent[0]->message

answered Jan 14, 2016 at 7:12

Prafulla Kumar Sahu

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Comments

Vegeta · Accepted Answer · 2016-01-14 07:17:32Z

0

Try this:

foreach( $emailContent as $index => $content )
    $name = $content[$index]->name;
    $email = $content[$index]->email; 
    echo 'Name: ' . $name .' | email: ' . $email.'<br>';
}

edited Jan 14, 2016 at 7:17

answered Jan 14, 2016 at 7:14

Vegeta

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1 Comment

Darren Over a year ago

It'd be -> not [] for proceeding properties of the object. ($emailContent[0]->name...etc)

Karthick Paramasivam · Accepted Answer · 2016-01-14 07:23:22Z

0

You have to get the object from the array first and then use -> to access the name.

Try this $name = $emailContent[0]->name;

answered Jan 14, 2016 at 7:23

Karthick Paramasivam

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Comments

Will · Accepted Answer · 2016-01-14 08:28:18Z

0

Try this instead:

$name = $emailContent[0]->name;
$email = $emailContent[0]->email;
$message = $emailContent[0]->message;

edited Jan 14, 2016 at 8:28

Will

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answered Jan 14, 2016 at 7:13

Ninju

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