String replace in PHP with return function

Question

In javascript you can define a return function when you do string replacements:

function miniTemplate(text, data) { 
    return text.replace(/\{\{(.+?)\}\}/g, function(a, b) {
        return typeof data[b] !== 'undefined' ? data[b] : '';
    });
}

This few lines of code allow me to create a very neat template system. The regular expression matches all the "{{something}}" strings inside the text variable and the return function matches if something is inside the object data, and if it is, it replaces it.

So,

text = "Hello {{var1}}, nice to meet {{var2}}";
data = { var1: "World", var2: "You" }
//result => "Hello World, nice to meet You"

Im trying to replicate this functionality is PHP, but the only solution that comes to my mind is using 2 cicles, one that parse each element of data array and the second one inside the first that looks for the string inside Text.

Is there a cleaner way in php?

have you tried doing the same as the js? Find out what's inside of the double brackets and doing a replace ? — Florian Humblot
– Florian Humblot, Commented Jan 27, 2016 at 11:03
You could come up with a solution based on preg_replace-callback(): php.net/manual/en/function.preg-replace-callback.php — Jan
– Jan, Commented Jan 27, 2016 at 11:03

Wiktor Stribiżew · Accepted Answer · 2016-01-27 11:29:23Z

3

You can use a preg_replace_callback just the same way as in JavaScript like this (pass the $data array to the preg_replace_callback using the uses keyword):

function miniTemplate($text, $data) { 
     return preg_replace_callback('~\{\{(.*?)}}~', function ($m) use ($data) {
         return isset($data[$m[1]]) ? $data[$m[1]] : $m[0]; 
     }, $text);
}
$text = "Hello {{var1}}, nice to meet {{var2}}";
$data = array("var1" => "World", "var2"=> "You");
echo miniTemplate($text, $data); // => Hello World, nice to meet You at {{var3}}

See IDEONE demo

If a value is missing in $data, the template string will be returned as we first check if it is present with isset($data[$m[1]]).

edited Jan 27, 2016 at 11:29

answered Jan 27, 2016 at 11:09

Wiktor Stribiżew

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2 Comments

DomingoSL Over a year ago

Perfect, I only suggest you to change the return line with return (isset($data[$m[1]])) ? $data[$m[1]] : ''; in the case the index is not present at least the function does not break

Wiktor Stribiżew Over a year ago

I updated to also support unavailable template data.

Tim Pietzcker · Accepted Answer · 2016-01-27 11:05:54Z

3

Yes, in PHP, there is a function preg_replace_callback() that you can pass a function to to handle the replacement:

$result = preg_replace_callback('/\{\{(.+?)\}\}/', 'do_replacement', $subject);

function do_replacement($groups) {
    // $groups[0] holds the entire regex match
    // $groups[1] holds the match for capturing group 1
    return ''; // actual program logic here
}

answered Jan 27, 2016 at 11:05

Tim Pietzcker

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Comments

Makwana Ketan · Accepted Answer · 2016-01-27 11:12:45Z

2

Try this code. it will definetely help you.

<?php
$text = "Hello {{var1}}, nice to meet {{var2}}";
$data = array("var1"=>"World","var2"=>"You");
foreach($data as $key => $value){
   $text = str_replace('{{'.$key.'}}', $value, $text);
}
echo $text;
?>

answered Jan 27, 2016 at 11:12

Makwana Ketan

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Comments

Anand Singh · Accepted Answer · 2016-01-27 11:10:26Z

1

You can use preg_replace_callback for this.

Code Example :

$result = preg_replace_callback('/\{\{(.+?)\}\}/', 'replacementFunction', $subject);

    function replacementFunction($groups) {
       //code login here
       return "value"; 
    }

edited Jan 27, 2016 at 11:10

answered Jan 27, 2016 at 11:05

Anand Singh

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Comments

Naumov · Accepted Answer · 2016-01-27 11:20:58Z

1

<?php 
    $data = array("var1" => "World", "var2" => "You");
    echo "Hello {$data['var1']}, nice to meet {$data['var2']}";
?>

refactoring...

answered Jan 27, 2016 at 11:20

Naumov

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Comments

Cihan Uygun · Accepted Answer · 2016-01-27 11:21:05Z

1

I think we do not need to think complex things about this need. If we try to keep it simple, you may use sprintf function for php to format text can you try the code below;

<?PHP
    $format = "Hello %s, nice to meet %s";
    $jsonData = "{\"var1\": \"World\", \"var2\": \"You\" }";
    $data = json_decode($jsonData);
    $result = sprintf($format,$data->var1,$data->var2);
    echo $result;
?>

Working example is here https://ideone.com/AGNZen

edited Jan 27, 2016 at 11:21

answered Jan 27, 2016 at 11:05

Cihan Uygun

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Comments

Vasim Shaikh · Accepted Answer · 2016-01-29 06:35:19Z

-1

A Quick Solution may be this one,

<?php
function ReplaceWord($find,$replace,$srcstring)
{
retrun str_replace($find,$replace,$srcstring);
}

echo ReplaceWord("WORLD","Peter","Hello world!");

?>

answered Jan 29, 2016 at 6:35

Vasim Shaikh

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