Bash break while loop by user input

Question

I got me a little stopwatch which I put into bashrc with the following code:

stopwatch() {
    date1=`date +%s`
    echo $1
    while true; do
            echo -ne "$(date -u --date @$((`date +%s` - $date1)) +%H:%M:%S)\r"
    done
}

The ouput would look like this while the time would just count up in the second line:

~$ stopwatch test
test
00:00:04

Now if I want to end the stopwatch I press Ctrl+C which gives me this:

~$ stopwatch test
test
^C:00:03

I'd like to end the loop while containing its ouput using e.g. my enter-key or any other. However if I use read it would wait for my input and hold the timer.

How do I keep the loop running until I press any key still preserving the output?

Edit: While am at it.. Is it possible to write the last output to a file before exiting?

Community · Accepted Answer · 2020-06-20 09:12:55Z

3

Adding to 123's answer, since I cannot comment. Instead of using

kill %1

use

kill $!

since, there may be several other jobs on the shell, kill %1 can kill other jobs as well, so to make it more flexible $! can be used.

$! will return process ID of last function ran on the current shell.

Run the loop in the background with &

Then pause function with read.

Write and kill when enter is pressed.

stopwatch() {
date1=`date +%s`
echo $1
while true; do
        echo -ne "$(date -u --date @$((`date +%s` - $date1)) +%H:%M:%S)\r"
done &
read
echo -ne "$(date -u --date @$((`date +%s` - $date1)) +%H:%M:%S)" > file
kill $!
}

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Feb 10, 2016 at 10:37

Nitish Jadia

394 bronze badges

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1 Comment

chris137 Over a year ago

This kind of contains the output. Looks like this: ~$ stopwatch test test [1] 3606 00:00:04

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