I want to convert a decimal number (loop index number) in a bash script to hexadecimal to be used by another command. Something like:
for ((i=1; i<=100; i++))
do
a=convert-to-decimal($i)
echo "$a"
done
Where a should be hexadecimal with four digits and hex identifier. For example if value of i is 100, the value of a should be 0x0064. How to do it?
You can use printf.
$ printf "0x%04x" 100
0x0064
In your example you'd probably use a="$(printf '0x%04x' $i)".
printf -v a '0x%04x' $i instead of process substitution.
# flag adds this automatically. So printf "%#06x" 100 gives 0x0064. The only question remains if the OP needs lower case of upper case hex digits. In the later case the X specifier should be used.That's what you're looking for
for i in seq 1 100;
do
printf '%x\n' $i
done
printf "%#06x" 100→0x0064