Question: How do I extract a character from a string that is an array?
Explained: Normal strings
string example=("Stack Over Flow");
cout<<example[1];
The output will be:
t
What I want is to extract a letter from an array of strings example:
string str[4];
str[0]="1st";
str[1]="2nd";
str[2]="3rd";
str[3]="4th";
cout<<str[2];
will print
3rd
how could i get the "t" from the str[0]?
just by doing as follow:
str[0][2]; // third character of first string
Some more examples:
string str[4];
str[0]="1st";
str[1]="2nd";
str[2]="3rd";
str[3]="4th";
cout<<str[0][2]<<endl; // t
cout<<str[2][1]<<endl; // r
cout<<str[3][2]<<endl; // h
[0] is for the first string in the array. [2] is for the third character in that string. What do you think [n] on a char would do?
string (string myArray[5]) you want to access the full string located at a specific index by doing myArray[string_index] , and then access the character of that particular string: myArray[string_index][char_index]
std::string array[4][4]. Otherwise you have to explain what is a 2 dimensional string.string myArray[4][5]). you need to access a character doing the following: myArray[string_row_index][string_col_index][char_index]std::string str[4];
str[0]="1st";
str[1]="2nd";
str[2]="3rd";
str[3]="4th";
Here str is an array of std::string objects. As you know you access elements of an array with operator[]. So the first string in the array is accessed with str[0].
std::string offers operator[] as well. With it you can access characters of the string.
So lets take it step by step.
str - array
str[0] - std::string
str[0][0] - first character of the string str[0]
YOu need one more operator[] call. str[2] is using the [] of the array and returns a reference to the array element at index 2. If you want to get the second character of the first array element then you need
str[0][2]
^ ^
string |
character
Class std::string has its own overloaded operator [] that you used in the first your code snippet
string example=("Stack Over Flow");
cout<<example[1];
If you have an array of objects of type std::string then at first you need to access the desired object stored in the array using the built-in subscript operator [] of arrays as for example
string str[4];
cout << str[1];
In this code snippet expression str[1] returns string stored in the second element (with index 1) of the array. Now you can apply the overloaded operator [] of the class std::string as for example
string str[4];
cout << str[1][1];
You get 't' instead of 's' because you are printing it like this cout<<example[1];
you sohuld do it like this:
cout<<example[0][2];
[1]? OP wanted the t; the third character.str[0]
string example=("Stack Over Flow");is not an array.std::stringobject, and e.g.str[0]is astd::stringobject.