PHP date_format(): How to format date from string value

Question

I have a bit of PHP code:

$exd = date_create('01 Dec, 2015');
$exd = date_format($exd, 'Y-m-d');
echo $exd;

Which is used for formatting the date. The expected output would be 2015-12-01 but it returns 2016-12-01. What am i missing?

you first need string to time convert..you can follow this stackoverflow.com/questions/6238992/… — user-4653387
– user-4653387, Commented Feb 18, 2016 at 5:29

Kevin · Accepted Answer · 2016-02-18 05:29:08Z

9

Use createFromFormat method first, provide the input format:

$exd = DateTime::createFromFormat('d M, Y', '01 Dec, 2015');
// arguments (<format of the input>, <the input itself>)
$exd = date_format($exd, 'Y-m-d'); // then choose whatever format you like
echo $exd;

answered Feb 18, 2016 at 5:29

Kevin

41.9k12 gold badges57 silver badges72 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Karthik N · Accepted Answer · 2016-02-18 05:37:06Z

4

The date_create() function accepts only the parameter link, This function is also and alias function of DateTime::__construct()

check the function date_create_from_format() its also a alias function of DateTime::createFromFormat(). Refer link

$exd = date_create_from_format('j M, Y', '01 Dec, 2015');
//$exd = date_create('01 Dec, 2015');
$exd = date_format($exd, 'Y-m-d');
echo $exd;

edited Feb 18, 2016 at 5:37

answered Feb 18, 2016 at 5:31

Karthik N

9518 silver badges16 bronze badges

Comments

Arun Panneerselvam · Accepted Answer · 2019-01-08 18:12:29Z

1

It can be a date function call simply. Use stringtotime for exact/precise date/time value

date("Y-m-d",strtotime("01 Dec 2015"))

When you run this code the out put will show

2015-12-01

this is because of the comma in the string which terminates the date string in the compiler. If you specify exactly the timezone (like $timezone = 'America/New_York) . parameter you can show precise time as well.

answered Jan 8, 2019 at 18:12

Arun Panneerselvam

2,3331 gold badge20 silver badges28 bronze badges

Comments

ketan · Accepted Answer · 2016-02-18 05:35:56Z

-2

i got the solution of your bug that is date_format(datae_variable,date_format);

<?php
     $exd = date_create('01 Dec, 2015');
     $exd1 = date_format($exd,"Y-m-d");//here you make mistake
     echo $exd1;
?>

answered Feb 18, 2016 at 5:35

ketan

125 bronze badges

4 Comments

mpsbhat Over a year ago

Good try... But please confirm the results before try. You can use phpfiddle.org for debugging and checking the results.

ketan Over a year ago

this code is also run phpfiddle.org check that first

mpsbhat Over a year ago

Please check the result. Expected would be 2015-12-01 but result was 2016-12-01

ketan Over a year ago

oooh am sorry i just check the format sorry ! r u from where? please

Collectives™ on Stack Overflow

PHP date_format(): How to format date from string value

4 Answers 4

Comments

Comments

Comments

4 Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

Comments

Comments

Comments

4 Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related