How to save None/Null if Index out of Range (Python/Django)

Question

I trying to loop through a list of objects and pull out their attributes and add them to a dictionary. In this list of objects some of the data was previously populated but sometimes there will be null or blank values. When the loop runs into the blank value it throws an "Index out of Range" Error.

obj = Idea.objects.get(name=idea_name)
new_obj = []
plan = ProductPlan.objects.all()
for product in plan:
    answers = product.question.answer_set.filter(idea=obj.id)
    new_plan = {"title": product.title, "answer": answers[0]}
    print new_plan
    new_obj.append(new_plan)

return render(request, 'idea.html', {"new_obj": new_obj, "obj":obj})

If the index is null, how do I just store it as empty.

Shang Wang · Accepted Answer · 2016-02-18 19:54:09Z

2

answers = product.question.answer_set.filter(idea=obj.id)
answer = answers[0] if answers.exists() else None
new_plan = {"title": product.title, "answer": answer}

Just in case you don't know, exists() would efficiently test whether a queryset is empty or not. Check django doc for more info.

answered Feb 18, 2016 at 19:54

Shang Wang

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