How to convert string with different parameters into integer?

Question

I want to write function, in-order to convert string, with many parameters, into integer. Problem is, how to define?

Like

def function_average(numbers)

where numbers is one string.

I want

function_average('40,50,60')
>>> 50

without cutting into different strings, but in one.

I tried different methods, but always have a mistakes, like invalid syntax.

Please share the code you have tried, and the errors you got. — Forge
– Forge, Commented Feb 21, 2016 at 8:14
Also show us the expected result. It's not clear what you want. — Cindy Meister
– Cindy Meister, Commented Feb 21, 2016 at 8:15

Wanming Zhang · Accepted Answer · 2016-02-21 08:18:56Z

1

just guess, from your function name and parameters ...

def function_average(numbers):
    numbers_list = numbers.split(',')
    return sum([int(x) for x in numbers_list]) / len(numbers_list)


print(function_average('40,50,60'))

answered Feb 21, 2016 at 8:18

Wanming Zhang

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4 Comments

User007 Over a year ago

Oh, this is interesting. So, split will separate strings?

Luka Rahne Over a year ago

sum(int(x) for x in numbers_list) no need to make list, when you can use generator

User007 Over a year ago

But what about ('3.4,3.5,6.7')? Is it other split for such numbers? Oh, I got, need to use float, instead of integer. Thanks!

Wanming Zhang Over a year ago

@LukaRahne, yes, for sum no need to make list, but also need get the length of the number list.

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