Regular Expression in java to get parameters from javascript methods

Question

Long story short, i would like to get the parameters list from JavaScript methods in Java. It works well if i got any parameters, but if the parameter list is empty it's just not working. For example

function() { return fn.num(tra.getMaster_id(fg)+1)

My regular expression is:

(?<=\({1}).*?(?=\){1})

The result i get:

tra.getMaster_id(fg

The result i want is the empty space between the ().

If i test it with Here everything is fine, but in java it didn't working yet :(

I would appreciate any ideas!

ndnenkov · Accepted Answer · 2016-03-05 09:49:36Z

1

First of all, you don't need {1} repetition quantifiers, everything is repeated just once by default. Secondly, since regexes in java are just strings that get interpreted, you have to escape escaping slashes (\):

(?<=\\().*?(?=\\))

Thirdly, you are getting the match that you want, it is just that there are more than one matches in this case. You are currently fetching the last one and not the first one.

answered Mar 5, 2016 at 9:49

ndnenkov

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4 Comments

hEngi Over a year ago

I checked with this tester link Is it possible to return just the first match?

ndnenkov Over a year ago

@SzékelyDávid, add a replacement and you will see that the empty space between () is also matched. Ofc you can get just the first match. Here is everything put together.

hEngi Over a year ago

Oh i see :D Thanks for your time!

ndnenkov Over a year ago

@SzékelyDávid, yw (:

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