I have an array and an input, if I input something I want to use .startswith() with my array, for example if I have this:
Array = ['foo','bar']
And if I input "fo" I want it to match it with "foo" and then return the index, in this case 0. How would I do this?
MaryPython's answer is generally fine. Alternatively, in O(n) instead of O(n^2), you could use
for index, item in enumerate(my_list):
if item.startswith('fo'):
print(index)
I've used enumerate to walk the index with the item
Note that Marky's implementation fails on this array
['fo','fo','fobar','fobar','hi']
because .index always returns the first instance of a repeated occurrence (but otherwise his solution is fine and intuitive)
Here is one solution. I iterated through the list and for each item checked if they start with the string 'fo' (or whatever your want to check with). If it starts with that string it prints the index of that item. I hope this helps!
Array = ['foo', 'bar']
for item in Array:
if item.startswith('fo'):
print(Array.index(item))
#!/usr/bin/python
# -*- coding: ascii -*-
Data = ['bleem', 'flargh', 'foo', 'bar' 'beep']
def array_startswith(search, array):
"""Search an iterable object in order to find the index of the first
.startswith(search) match of the items."""
for index, item in enumerate(array):
if item.startswith(search):
return(index)
raise(KeyError)
## Give some sort of error. You probably want to raise an error rather
## than returning None, as this might cause a logic error in the
## later program. I think KeyError is correct, based on the question.
## See Effective Python by Brett Slatkin, Page 29...
if __name__ == '__main__':
lookfor='fo'
try:
result=array_startswith(lookfor, Data)
except KeyError as e:
print("'{0}' not found in Data, Sorry...".format(lookfor))
else:
print("Index where '{0}' is found is: {1}. Found:{2}".format(lookfor,
result, Data[result]))
finally:
print("Try/Except/Else/Finally Cleanup happens here...")
print("Program done.")
import this into the python shell to see), "Simple is better than complex.".
a = ['foo', 'bar']or isfooa variable there...startswith().