I am writing an automation script in python using argparse module in which I want to use the -s as an option which takes file/file path as an argument. Can somebody help me to do this?
Example: ./argtest.py -s /home/test/hello.txt
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Did you read the documentation for the module yet? It includes examples of how to do this. Where did you get stuck when you tried?Martijn Pieters– Martijn Pieters2016-03-23 00:33:30 +00:00Commented Mar 23, 2016 at 0:33
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2 Answers
Just do this:
import argparse
parser = argparse.ArgumentParser(description="My program!", formatter_class=argparse.RawTextHelpFormatter)
parser.add_argument("-s", type=argparse.FileType('r'), help="Filename to be passed")
args = vars(parser.parse_args())
open_file = args.s
If you want to open the file for writing, just change r to w in type=argparse.FileType('r'). You could also change it to a, r+, w+, etc.
1 Comment
hpaulj
I would omit the
nargs=1; the default nargs value is usually better.You can use
import argparse
parse = argparse.ArgumentParser()
parse.add_argument("-s")
args = parse.parse_args()
# print argument of -s
print('argument: ',args.s)
Suppose the above code is stored in the file example.py
$ python example.py -s /home/test/hello.txt
argument: /home/test/hello.txt
You can click here(Python3.x) or here(Python2.x) to learn more.
2 Comments
Alagu Jeeva
Hi zondo, I used your code but it throws me an error like "AttributeError: 'dict' has no attribute 's'. Kindly help
Ren
@AlaguJeeva - Try use
python-3.x