python - check string contain a valid regular expression python

Question

In order to check to see if a string is a valid regular expression python.

Example:

asdasd="([0-9]{1})";APRI="([0-9]{9})";ADD="([0-9]{1})"

How can i check string is contain valid regular expression ?

Thanks,

alecxe · Accepted Answer · 2016-03-23 04:03:20Z

4

Apply the EAFP approach, compile the expression and handle errors.

For example, unbalanced parenthesis:

>>> import re
>>> re.compile(r"(test")
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/Users/user/.virtualenvs/so/lib/python2.7/re.py", line 194, in compile
    return _compile(pattern, flags)
  File "/Users/user/.virtualenvs/so/lib/python2.7/re.py", line 251, in _compile
    raise error, v # invalid expression
sre_constants.error: unbalanced parenthesis

answered Mar 23, 2016 at 4:03

alecxe

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Comments

Brian Cain · Accepted Answer · 2016-03-23 04:03:07Z

1

EAFP

Compile it and see.

re.compile(asdasd)

answered Mar 23, 2016 at 4:03

Brian Cain

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Comments

ode2k · Accepted Answer · 2016-03-23 04:05:01Z

0

Try your regex code in the Online Regex Tester

https://regex101.com/

Your first example: https://regex101.com/r/gN1tG8/1

answered Mar 23, 2016 at 4:05

ode2k

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