PHP PDO count and sum value from MySQL table

Question

Well, I'm pretty sure this is just a novice question, so please forgive me for that, but I feel like I'm losing my mind.

I have a simple MySQL rating table and I need to count rows and to sum rates values (int) with PHP PDO

$sql = "SELECT rate FROM rating_table";
$query = $db->query($sql);            

$rate_times = count($query->fetchAll()); // it works! 
echo '<p>'.$rate_times.'</p>';

$sum_rates = array_sum($query->fetchAll()); // it doesn't work!
echo '<p>'.$sum_rates.'</p>';

Thank you in advance for any suggestion

@naf4me here for you: array(78) { [0]=> array(1) { ["rate"]=> int(4) } [1]=> array(1) { ["rate"]=> int(5) } [2]=> array(1) { ["rate"]=> int(3) } .... [77]=> array(1) { ["rate"]=> int(5) } } — Alt
– Alt, Commented Apr 14, 2016 at 9:10
using mysql functions sum and count is much better solution (and faster too) — calvix
– calvix, Commented Apr 14, 2016 at 9:16
Array_sum sums the array like : $a = [1,4,6,8,4]. array_sum($a) will output 23. — naf4me
– naf4me, Commented Apr 14, 2016 at 9:18

heximal · Accepted Answer · 2016-04-14 08:57:47Z

1

If I understand you right, all you have to do is to modify your sql request, this will return a single row

sql = "SELECT sum(rate) as rate_sum, count(*) as record_count FROM rating_table";
$query = $db->query($sql);            
$row = $query->fetch(PDO::FETCH_ASSOC);
if ($row) {
  $sum = $row['rate_sum'];
  $count = $row['record_count'];
}

answered Apr 14, 2016 at 8:57

heximal

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