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Push multi values in javascript array and get the first element?

Below, I am trying to push 3 different values in a array:

var a = [];
a.push([1, 'b', 'c']);
DBG.write("test:" + a[0]); //output: 1, b, c

how to print the the first element on this array?

output should be: 1

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4
  • 2
    a[0][0] as a[0] is an array! Commented May 3, 2016 at 13:38
  • To build on what @Rayon said, Array.push expects direct values, and not an array. a.push([1, 'b', 'c']) is pushing an array to the first element of a. Commented May 3, 2016 at 13:42
  • @ArcSine, "Array.push expects direct values, and not an array" .. No buddy! It is ok with anything.. undefined as well.. Commented May 3, 2016 at 13:43
  • It accepts arrays, but it will add it as an array. a.push(1,2,3) is different than a.push([1,2,3]) Commented May 3, 2016 at 13:54

3 Answers 3

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3

You are pushing in an array. Try

a.push(1, 'b', 'c');

to push in 3 separate values.

And to print it:

DBG.write("test:" + a[0]);

(or, if you want to push in the array like you did in your question, use 

DBG.write("test:" + a[0][0]);

to get the first element of that array).

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2 Comments

I would use this. Pushing an array into an array and only wanting to push out the inner array makes no sense.
Simple & clean. +1
1 
a[0] // output [1, 'b', 'c']

By doing 

DBG.write("test:" + a[0][0]); // output 1
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1 Comment

This is giving the right result, but I would recommend to use the other solution, since this is the behavior I think would make more sense.
1

If you want to add items from array then use concat. In your case when you push and array into an array then it becomes a multi-dimensional array (assuming that was not the intention), it became [[1,'b','c']].

Replace 

a.push([1, 'b', 'c']);

with

a = a.concat([1, 'b', 'c']);

You can print the first element by doing same thing DBG.write("test:" + a[0]);

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5 Comments

@jhon you can print the same way you intended to print earlier.
@jhon you can print 1 by doing DBG.write("test:" + a[0]);
Why not a.push(1, 'b', 'c');?
@Cerbrus he sure can, but I assumed that he already has an array.
Good point! concat's the way to go then.