Javascript/JQuery join() method error when using on an array

Question

I'm trying to loop through my JSON array and assign a specific key of each element into a variable:

Here is the array:

"joining_profiles": [
      {
        "pic": "http://graph.facebook.com/832332325303/picture", 
        "id": 3, 
        "name": "Test2 Gmail"
      }, 
      {
        "pic": "http://graph.facebook.com/620223232354388/picture", 
        "id": 81, 
        "name": "Lawson G."
      }, 
      {
        "pic": "http://graph.facebook.com/6693273223239/picture", 
        "id": 83, 
        "name": "Mark Zuckerberg"
      }
    ]

Here is my javascript:

for (var q = 0; q < pings[i].joining_profiles.length; q++) {
          var joiners = pings[i].joining_profiles[q].name;
          joiners.join();

Basically I need to assign each "name" entry into a joined variable separated by a comma to use in a closured function.

The error im getting from the console is:

TypeError: Result of expression 'joiners.join' [undefined] is not a function.

meder omuraliev · Accepted Answer · 2010-09-15 04:22:23Z

2

.name is a string. You're calling .join() on a string which doesn't have a join method.

''.join()
TypeError: Object  has no method 'join'

answered Sep 15, 2010 at 4:22

meder omuraliev

187k76 gold badges401 silver badges443 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Sidharth Panwar · Accepted Answer · 2010-09-15 05:37:40Z

0

Try this (inside your for loop):

Updated:

var joiners;  
for ...
{
joiners += pings[i].joining_profiles[q].name + " ";  
var newText = RTRIM(joiners).split(" ").join(","); 
}

edited Sep 15, 2010 at 5:37

answered Sep 15, 2010 at 4:22

Sidharth Panwar

4,6646 gold badges31 silver badges36 bronze badges

1 Comment

Sachin Over a year ago

that didnt work... the console is spitting out a parse error because of the var joiners +=

Collectives™ on Stack Overflow

Javascript/JQuery join() method error when using on an array

2 Answers 2

Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related