Comparing Lists elements and sets in python

Question

First I'll show my code and then I'll explain:

for eachfile in matches:
    if eachfile in set1:
        print 'find one match'
        shutil.copy2(eachfile, '/Users/r2-d2/Desktop/folder')
        print 'copy done'

matches is a list like this:

[fooFILE_Aspam.txt, barFILE_B.CSV, codeFILE_Cdog.vcf]

set1 is a set like which looks like this:

(FILE_A, FILE_B, FILE_F...)

I'm iterating over the list to check if inside each entry there's any of the elements of the set. If it does I copy the entry away. In the above example scenario I expect a match for FILE_A and FILE_B. I know that the keyword in would work the other way around but I can't find an elegant solution without using another loop.

Are these strings inside the list/set?

user5547025
– user5547025

2016-05-12 14:08:53 +00:00
Commented May 12, 2016 at 14:08 — user5547025
– user5547025, Commented May 12, 2016 at 14:08

Moses Koledoye · Accepted Answer · 2016-05-12 15:25:26Z

1

Set1 is not a set (like you stated) but a tuple, so you need to cast and then you can use a set intersection to filter duplicates across both

 matching_files = list(set(matches).intersection(set(set1)))

 for file in matching_files:
     # Do your copy
     pass

edited May 12, 2016 at 15:25

answered May 12, 2016 at 14:13

Moses Koledoye

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Comments

shipperizer · Accepted Answer · 2016-05-12 14:12:52Z

0

what about intersection between sets?and then you copy the result?Not really sure though if you are looking for a math in the string of if the elements in the list are the "same" as the one in the set

answered May 12, 2016 at 14:12

shipperizer

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Comments

C Panda · Accepted Answer · 2016-05-12 14:18:28Z

0

There are many ways to do this.

import re
pat = re.compile('|'.join(set1))
for match in matches:
    if pat.search(match):
        # do stuff

But I would probably introduce the filter with the help of regex (or possibly fnmatch) while calculating matches

answered May 12, 2016 at 14:18

C Panda

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Hooting · Accepted Answer · 2016-05-12 14:19:19Z

0

use any to check if any matches eachfile.

matches = ['fooFILE_Aspam.txt', 'barFILE_B.CSV', 'codeFILE_Cdog.vcf']
set1 = ('FILE_A', 'FILE_B', 'FILE_F')

for eachfile in matches:
    if any([x in eachfile for x in set1]):
        print eachfile

answered May 12, 2016 at 14:19

Hooting

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hilberts_drinking_problem · Accepted Answer · 2016-05-12 14:25:23Z

0

First, in operator applies to both set and str. In the former case, you are checking for exact string match; in the second, for contiguous substring inclusion. I assume you are after the latter, so this should work.

matches = ['fooFILE_Aspam.txt', 'barFILE_B.CSV', 'codeFILE_Cdog.vcf']
set1 = {'FILE_A', 'FILE_B', 'FILE_F'}

to_move = [fname for fname in matches if any(t in fname for t in set1)]

# In [39]: q.to_move
# Out[39]: ['fooFILE_Aspam.txt', 'barFILE_B.CSV']

answered May 12, 2016 at 14:25

hilberts_drinking_problem

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Comments

Tjaart · Accepted Answer · 2016-05-12 15:51:43Z

0

You can use this:

for eachfile in [x for x in matches if x in set1]:
    print 'find one match'
    shutil.copy2(eachfile, '/Users/r2-d2/Desktop/folder')
    print 'copy done'

Or, do it inside the for loop - list:

def shCopy(file,dest='/Users/r2-d2/Desktop/folder'):
    print 'find one match'
    shutil.copy2(file, dest)
    print 'copy done'

[shCopy(x) for x in matches if x in set1]

edited May 12, 2016 at 15:51

answered May 12, 2016 at 15:01

Tjaart

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