I am trying to find an element using xpath.
I tried this method:
if(a_chromeWebdriver.findElement(By.xpath(XPATH1)) != null){
homeTable = a_chromeWebdriver.findElement(By.xpath(XPATH1));
}
else{
homeTable = a_chromeWebdriver.findElement(By.xpath(XPATH2));
}
I assumed that if the first xpath won't be found, it will try he second one. But it throws an exception of element not found.
I also tried to check size = 0 instead of null, but got the same result.
You can use this method to check whether your xpath is present or not :
create a method : isElementPresent
public boolean isElementPresent(By by) {
try {
driver.findElements(by);
return true;
} catch (org.openqa.selenium.NoSuchElementException e) {
return false;
}
}
Call it using xpath like this :
isElementPresent(By.xpath(XPATH1));
So your code would become :
if(isElementPresent(By.xpath(XPATH1))){
homeTable = a_chromeWebdriver.findElement(By.xpath(XPATH1));
}
else{
homeTable = a_chromeWebdriver.findElement(By.xpath(XPATH2));
}
You could use findElements instead of findElement and then check the size:
List<WebElement> elements = a_chromeWebdriver.findElements(By.xpath(XPATH1));
if(elements.size() > 0){
homeTable = elements.get(0);
} else{
homeTable = a_chromeWebdriver.findElement(By.xpath(XPATH2));
}
But a better way would be to combine the 2 XPath in a single one with |:
homeTable = a_chromeWebdriver.findElement(By.xpath(XPATH1 + "|" + XPATH2));
You could create a method,
public WebElement getElement(By by) {
try {
return a_chromeWebdriver.findElement(by);
} catch (org.openqa.selenium.NoSuchElementException e) {
return null;
}
}
You could use it as follows,
WebElement element = getElement(By.xpath(XPATH1));
if (element == null)
element = getElement(By.xpath(XPATH2));
First add implicit wait to your code that will handle synchronization issues
driver.manage().timeouts().implicitlyWait(30, TimeUnit.SECONDS);
Add OR Operator rather than adding condition as other answers points out. homeTable = a_chromeWebdriver.findElement(By.xpath(XPATH1 | XPATH2));
