New object using object's class instance

Question

Today I just discovered that in php you can do :

$instance = new MyObject();

// Here $instance->getName() == 'First Instance'
$instance->setName('First Instance');

// Here $newInstance->getName() == null
$newInstance = new $instance();

Obviously $newInstance is a valid 'MyObject' object.

Can someone tell me what this way to go involve and if it is or isn't a must NOT do?

Thx mates !

What are you trying to achieve? The last line of that code makes no sense. I would have expected it to fatal, but apparently not O_o — Jonnix
– Jonnix, Commented Jun 9, 2016 at 12:41
I am using a function which takes an object in parameter, which I don't know the class, use a function to get more details about the object then cast a new class instance sending using all the details. I create a new class because this function is part of a project where I get object details using an API and each function which get information from this API return a 'new MyObject($apiResults)' so I want to keep this way to go even for this function which is more general... — LordWeedlle
– LordWeedlle, Commented Jun 9, 2016 at 12:47

Parthapratim Neog · Accepted Answer · 2016-06-09 12:46:29Z

1

You need to use what is called a "Singleton Design Pattern" to achieve your goal, which, if I'm not wrong is that you want to use the same Object, every time an Object of the class is created.

class Singleton {
private static $instance;

public function __construct() {
        if (isset(self::$instance)) {
            $object         = __CLASS__;
            self::$instance = new $object;
            return self::$instance;
        }
    }
}

Here, the constructor checks if there is already an instance of the class, if there is, it returns that object itself. Else it creates a new one.

answered Jun 9, 2016 at 12:46

Parthapratim Neog

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