I want to sort each string of array of strings , here is my code that i tried.
#include <iostream>
#include <algorithm>
void _sort_word(char *str)
{
int len = strlen(str);
std::sort(str,str+len); // program get stuck here.
}
int main()
{
char *str[] = {"hello", "world"};
for(int i=0;i<2;i++){
_sort_word(str[i]);
cout << str[i] << "\n";
}
}
I want to know is sort(str,str+len); a valid statement here, if not what should be done instead ?
First of all string literals in C++ have types of constant character arrays. So the correct array declaration will look like
const char *str[] = {"hello", "world"};
^^^^^
Thus the string literals pointed to by the elements of the array are immutable.
You should declare at least a two dimensional array.
Here is a demonstrative program
#include <iostream>
#include <algorithm>
#include <cstring>
void sort_word( char *s )
{
size_t l = std::strlen( s );
std::sort( s, s + l );
}
int main()
{
char str[][6] = { "hello", "world" };
for ( auto &s : str ) sort_word( s );
for ( auto &s : str ) std::cout << s << std::endl;
return 0;
}
Its output is
ehllo
dlorw
If your compiler does not support the range based for statement then you can write instead
for ( size_t i = 0; i < sizeof( str ) / sizeof( *str ); i++ ) sort_word( str[i] );
std::sort()needs write access the underlying memory, which currently is a char string literal and you can't change anything there.char str[2][6] = {"hello", "world"};if the max length is6.