request csv format data from url using python

Question

i wana simply send a request to the following url and recive data in csv format and save on the following location,but doest not work!any help will be appreciated

from urllib import  request

my_url='http://real-chart.finance.yahoo.com/table.csv?s=CSV&a=07&b=9&  c=1996&d=05&e=26&f=2016&g=d&ignore=.csv'

def rciveURL(getURL):
response=request.urlopen(getURL)
csv=response.read()
csv_str=str(csv)
mydstination=r'mori.csv'
fx=open(mydstination,"w")
for line in csv_str:
  fx.write(line+"\n")
  fx.closed()

  rciveURL(my_url)

Indentation level at function rciveURL() seems wrong. Is it just a typo? — Absolut
– Absolut, Commented Jun 26, 2016 at 17:20
As noted, your code isn't formatted properly. Also, requests is a third party replacement for the standard urllib. So pick which one you want. Requests is easier to understand — joel goldstick
– joel goldstick, Commented Jun 26, 2016 at 17:25

Prajwal K R · Accepted Answer · 2016-06-26 17:22:08Z

1

The correct way to receive a file from url and save a file at save_dest is:

import urllib
file = urllib.URLopener()
file.retrieve(url, save_dest)

answered Jun 26, 2016 at 17:22

Prajwal K R

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