Passing a php array as a json element with json_encode in a hidden input

Question

I'm trying to work with an array in javascript so I am trying to Json_encode my php array as a hidden value. This is giving me this error Notice: Array to string conversion in.. Is this not possible? Am I going about this wrong?

$pic_array = array();
$titles = array();
$descriptions = array();
while ($row = $result->fetch_assoc()) {
    $pic_array[$count] = $row['pic_url'];
    $titles[$count] = $row['title'];
    $descriptions[$count] = $row['description'];
    $count++;
}

echo "<input id='json_pics' type='hidden' value='json_encode($pic_array)'/>";

The json_encode has to be outside quotes, for php to execute it. echo "<input id='json_pics' type='hidden' value='".json_encode($pic_array)."'/>"; — Fredster
– Fredster, Commented Jun 27, 2016 at 18:21

u_mulder · Accepted Answer · 2016-06-27 18:21:06Z

2

Proper code is

echo "<input id='json_pics' type='hidden' value='" . json_encode($pic_array) . "'/>";

In your current code php doesn't understand that you try to use json_encode function and just sees $pic_array variable which is array.

answered Jun 27, 2016 at 18:21

u_mulder

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cb0 · Accepted Answer · 2016-06-27 18:26:06Z

1

For better readability I would recommand using printf for inserting the json encoded string.

echo sprintf("<input id='json_pics' type='hidden' value='%s'/>", json_encode($pic_array));

answered Jun 27, 2016 at 18:26

cb0

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