for i in $LIST
do
CFG=`ssh $i "cat log.txt|awk '{print $2}'"`
for j in $CFG
do
echo $j
done
done
Say I want to print 2nd field in the log file on a couple remote host. In above script, print $2 doesn't work. How can I fix this? Thanks.
Depending on the number of shell expansions and type of quoting multiple backslash escapes are needed:
awk '{ print $2 }' log.txt # none
ssh $server "awk '{ print \$2 }' log.txt" # one
CFG=`ssh $server "awk '{ print \\$2 }' log.txt"` # two
CFG=$(ssh $server "awk '{ print \$2 }' log.txt") # one (!)
As a trick you can put a space between the dollar sign and the two to prevent all $ expansion. Awk will still glue it together:
CFG=`ssh $i "cat log.txt|awk '{print $ 2}'"`
try
for i in $LIST
do
ssh $i "cat log.txt|awk '{print \$2}'"
done
Make sure you're escaping the $2 from the shell - the ssh command you end up sending right now is something like this: ssh listvalue cat log.txt|awk '{print }'
for server in $LIST
do
ssh "$server" 'awk "{print $2}" log.txt'
done
single-quote and the double-quote. words beginning with $) inside double-quote ("). ') stops Bash from looking for variables inside.user131527 and psj suggested, escaping $2 with \ should also have worked (depending on how your Bash is configured).I was able to put awk in a double for loop
for i in 1 2 3 4;do
for j in $\(ls | awk -v I=$i '{print $I}');
echo $j
done;
done
```
`code` for code-line and 4 spaces for code-blockLose the cat. Its useless..
for server in $LIST
do
ssh "$server" "awk '{print \$2}' log.txt"
don
catis unnecessary:CFG=$(ssh $i "awk '{print $2}' log.txt")