Create array of arrays by assigning keys while creating sub arrays

Question

I could write it out like this.

 $key = "sid";
 $values = array(1,2,3);
 $desired_array = array();

 foreach($values as $value){
     $desired_array[] = array($key => $value);
 }

 print_r($desired_array);

The output would look like this.

Array
(
    [0] => Array
        (
            [sid] => 1
        )

    [1] => Array
        (
            [sid] => 2
        )

    [2] => Array
        (
            [sid] => 3
        )     
)

I was hoping there was a fancy php array function I didn't know about that could create that for me so keep my code terser.

Here's the completed solution, maybe it's not much shorter but I'm always happy when I get to use array_map.

 $key = "sid";
 $values = array(1,2,3);
 $desired_array = array_map(function($value) use($key){
    return array($key=>$value);
 },$values);

RomanPerekhrest · Accepted Answer · 2016-07-23 18:42:50Z

2

The alternative solution using array_map function:

$desired_array = array_map(function($v) use($key){ return [$key => $v]; }, $values);

answered Jul 23, 2016 at 18:42

RomanPerekhrest

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1 Comment

jbrahy Over a year ago

The use($key) is exactly what I needed to make array_map work the way I needed. Thanks!

random_user_name · Accepted Answer · 2016-07-23 18:46:50Z

2

You may be looking for array_map.

It would work something like this:

$array = [1, 2, 3];
$desired = array_map(function ($item) {return ['sid' => $item];}, $array);

I believe this link should work for a demonstration as well.

edited Jul 23, 2016 at 18:46

random_user_name

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answered Jul 23, 2016 at 18:43

Marshall Davis

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2 Comments

jbrahy Over a year ago

Thanks, but it was the use() that I was missing when I initially tried array_map. It was in RomanPerekhrest's answer.

Marshall Davis Over a year ago

Yep, if you want a variable key his is the better answer.

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