php array and for loop - add <br> after 5 resultss [duplicate]

Question

This is my code:

$sm2 = array( "angry", "cool", "cry", "happy", "heart", "kiss", "mute", "sad", "smile"); 

for($j=0;$j<count($sm2); $j++) {
    $data=$data . "<img id='". $sm2[$j] ."' src='images/emotions/" . $sm2[$j] . ".png' data-toggle='tooltip' title=". $sm2[$j] ."  width='32' height='32' style='margin:5px;'
    onclick='insertEmoticons(this.id);'/>";
}

How can I insert a <br> tag after 5 results because i don't want everything to be on one row.

modulus ($i % 5 == 0) - as per stackoverflow.com/questions/8135404/php-modulus-in-a-loop which this is also a possible duplicate — Funk Forty Niner
– Funk Forty Niner, Commented Jul 30, 2016 at 1:58

Funk Forty Niner · Accepted Answer · 2016-07-30 02:10:05Z

2

Use the Modulus operator.

<?php
$sm2 = array( "angry", "cool", "cry", "happy", "heart", "kiss", "mute", "sad", "smile"); 
for($j=0;$j<count($sm2); $j++) {
     if(!empty($j) && $j % 5 == 0) {
          echo '<br>';
     }
     echo $sm2[$j];
}

Output:

angrycoolcryhappyheart<br>kissmutesadsmile

Demo: https://eval.in/614166

Or with your actual code:

for($j=0;$j<count($sm2); $j++) {
    if(!empty($j) && $j % 5 == 0) {
          $data .= '<br>';
    }
    $data=$data . "<img id='". $sm2[$j] ."' src='images/emotions/" . $sm2[$j] . ".png' data-toggle='tooltip' title=". $sm2[$j] ."  width='32' height='32' style='margin:5px;'
    onclick='insertEmoticons(this.id);'/>";
}

Also note $data=$data . is the same as $data .= ....

edited Jul 30, 2016 at 2:10

Funk Forty Niner

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answered Jul 30, 2016 at 1:59

chris85

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Comments

Robert Columbia · Accepted Answer · 2016-07-30 01:58:58Z

0

$sm2 = array( "angry", "cool", "cry", "happy", "heart", "kiss", "mute", "sad", "smile"); 

for($j=0;$j<count($sm2); $j++) {
    $data=$data . "<img id='". $sm2[$j] ."' src='images/emotions/" . $sm2[$j] . ".png' data-toggle='tooltip' title=". $sm2[$j] ."  width='32' height='32' style='margin:5px;' onclick='insertEmoticons(this.id);'/>";
    if ( (($j+1) % 5) == 0)
    {
        $data = $data . "<br>";
    }

}

answered Jul 30, 2016 at 1:58

Robert Columbia

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1 Comment

Mensur Over a year ago

That code mate is giving syntax error :)

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