Print html content in php function

Question

I'm trying to create a function 'header' which will print html content (doctype, html, head, body, etc) - but when I'm looking in a site source, all of that stuff is in one line, not in a tree hirearchy...

public function header() {
        print(
                '<!DOCTYPE HTML>'
                . '<html>'
                . '<head>'
                . '<meta charset="utf-8"/>'
                );

And when I'm looking in the web source the output looks like:

<!DOCTYPE HTML><html><head><meta charset="utf-8"/>

I would like it to look more like standard html tree:

<!DOCTYPE HTML>
<html>
    <head>
        <meta charset="utf-8"/>

How can I do that? What are the options ?

EDIT:

Some of You showed me an echo option - it works, but it looks really bad in a php file - like:

            public function header() {
echo "<!DOCTYPE HTML>
<html>
    <head>
        <meta charset='utf-8' />
    </head>
    <body>
    </body>
</html>            
";

Don't focus too much on code appearance. There will be many other point far more important to think about (security, optimisation, evolution) to achieve your projects. — technico
– technico, Commented Aug 6, 2016 at 9:07

technico · Accepted Answer · 2016-08-06 08:46:14Z

3

The most classic way, using echo :

echo '<!DOCTYPE HTML>
<html>
    <head>
        <meta charset="utf-8"/>

';

answered Aug 6, 2016 at 8:46

technico

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3 Comments

user6685192 Over a year ago

but it looks weak as fk in the php file

technico Over a year ago

a bit rough but efficient. I'll try another answer to fit your esthetic request :)

user6685192 Over a year ago

that would be great - please check edit in main post

Sajid Manzoor · Accepted Answer · 2016-08-06 18:51:28Z

see below methods for printing HTML inside PHP code block

FOR SHORT HTML CONTENTS

echo ' <div class="myClass"> Some Text here. Some text here </p> ';

FOR SHORT HTML CONTENTS WITH PHP variable concatenation

$myName='Optimum';
echo ' <div class="myClass"> My Name is '. $myName .' </p> ';

FOR LONG CONTENT

$html.='';
$phpVariable ='Dummy content'
$html.='<div class="wrapper">'
$html.='<div class="content">';
$html.='<p> My content here'. $phpVariable .' </p>';
$html.='</div>';
$html.='</div>';

echo $html;

According to your scenario

  <?php 
 public function header() { // SOME NECESSARY PHP CODE ?>
 <!DOCTYPE HTML>
     <html>
         <head>
             <meta charset="<?php //echo get_chartset ?>"/>
                 <link rel="stylesheet" type="text/css" href="<?php //echo_css_path ?>">

  } 
  ?>

This will echo/ print clean HTML code in front.

Mureinik · Accepted Answer · 2016-08-06 08:49:12Z

0

You could introduce tabs when you print:

print("<!DOCTYPE HTML>"
      . "<html>"
      . "\t<head>"
      . "\t\t<meta charset=\"utf-8\"/>"
     );

edited Aug 6, 2016 at 8:49

answered Aug 6, 2016 at 8:46

Mureinik

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3 Comments

Mureinik Over a year ago

@user6685192 arg, forgot yo change the quote type - see edited answer.

user6685192 Over a year ago

I've changed it to double quotes, but the result is still weak (there are tabs, but it's still in one line)

Abela Over a year ago

for s&g i just tried this... within google chrome and ms edge, view source it is all on a single line.

Zayn Ali · Accepted Answer · 2016-08-06 09:13:23Z

0

Another approach would be to simply just separate your html template file (Format it however you want) and then just require it with passed data in your function like so

my_view.php

<!DOCTYPE html>
<html lang="en">
<head>
    <meta charset="UTF-8">
    <title>Document</title>
</head>
<body>
    <h1><?= $heading ?></h1>
</body>
</html>

Your function

function showTemplate($view, array $data) {
    extract($data);
    require $view . '.php';
}

That way you can just call to output your view with data, like this

showTemplate('my_view', [ 'heading' => 'Awesome Page' ]);

This way your template and data would be more organized and pretty.

edited Aug 6, 2016 at 9:13

answered Aug 6, 2016 at 8:49

Zayn Ali

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2 Comments

Abela Over a year ago

This does work, but should probably remove the line break between opening " and <!DOCTYPE HTML> as it causes a line break at the very top of the view source.

user6685192 Over a year ago

but it looks really bad in a php file

technico · Accepted Answer · 2016-08-06 09:45:21Z

0

Another way, for doing this :

<?php
function myheader() {
?><!DOCTYPE HTML>
<html>
   <head>
      <meta charset="utf-8"/>

<?php } ?>

I redefined the function name to avoid conflict, (off-topic). I don't know how such a code should be indented ...

edited Aug 6, 2016 at 9:45

answered Aug 6, 2016 at 8:57

technico

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