ruby how to remove elements from hash array?

Question

I am trying to remove the entire row for id and name for 001 and 002from the sample:

sample = [{"id"=>"000", "name"=>"Bob"},
     {"id"=>"001", "name"=>"Sally"},
     {"id"=>"002", "name"=>"Spike"},
     {"id"=>"003", "name"=>"Junior"},
     {"id"=>"004", "name"=>"Tater"}]

remove_ele = ["001","002"]

I have tried the following, but it doesn't seem to work:

sample.delete_if { |key, value| sample[x]["id"] == remove_ele[x] }

essentially, i'm trying to compare the 2 and any matches in remove_ele it will just delete the entire row/element in sample.

Please assist in best way to do this in ruby.

max pleaner · Accepted Answer · 2016-08-09 22:34:05Z

5

there are a few problems with this block you've provided to delete_if:

sample.delete_if { |key, value| sample[x]["id"] == remove_ele[x] }

Since sample is an array of hashes, using the delete_if iterator will pass a hash to the block. I.e. it should be |hash| instead of |key, value|.

Secondly, x will not be defined in your block.

A functional solution would be this:

remove_ele.each do |id_to_remove|
  sample.delete_if { |hash| hash['id'] == id_to_remove }
end

Alternatively, which does the same thing:

sample.delete_if { |hash| remove_ele.include? hash['id'] }

answered Aug 9, 2016 at 22:34

max pleaner

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1 Comment

The Gugaru Over a year ago

Upvotted because you provided explanation with your code!

JimF · Accepted Answer · 2016-08-09 22:36:27Z

2

sample.delete_if {|x| remove_ele.include? x['id'] }

answered Aug 9, 2016 at 22:36

JimF

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1 Comment

The Gugaru Over a year ago

Down voted due to lack of explanation. Providing the code without explanations does nothing for the op

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