Get path in svg using Selenium (Python)

Question

I have the following code which find all g's in svg, yet how could I get those path elements inside g's and their path value?

I am testing with this website: http://www.totalcorner.com/match/live_stats/57565755

related code:

nodes = self.driver.find_elements_by_xpath("//div[@id='all_container']/*[@id='highcharts-0']/*[name()='svg']/*[name()='g']")

I have already tried this:

nodes = self.driver.find_elements_by_xpath("//div[@id='all_container']/*[@id='highcharts-0']/*[name()='svg']/*[name()='g']/*[name()='path']")

yet what I get is something like this:

[<selenium.webdriver.remote.webelement.WebElement (session="fb86fb35-d2fa-974a-af32-a15db1b7459d", element="{c1dad34f-764d-0249-9302-215dd9ae9cd8}")>, <selenium.webdriver.remote.webelement.WebElement (session="fb86fb35-d2fa-974a-af32-a15db1b7459d", element="{a53816f4-9952-ab49-87ac-5d79538a855d}")>, ...]

How could I use this to find the path value? thanks a lot

My updated solution:

thanks everyone's effort. After Robert Longson's updated answer, I think the following is the better solution:

nodes = driver.find_elements_by_xpath("//div[@id='all_container']/*[@id='highcharts-0']/*[name()='svg']/*[name()='g']/*[name()='path']")
for node in nodes:
    print(node.get_attribute("d"))

Since I cannot differentiate paths if using driver.find_elements_by_tag_name, I think the answer above is better.

Ulf Gjerdingen · Accepted Answer · 2016-08-21 15:22:03Z

3

You are getting a list, so try:

for node in nodes:
    print(node.text)

if a you are looking for a value of an attribute then use the following (href here as an example):

print(node.get_attribute('href'))

edited Aug 21, 2016 at 15:22

answered Aug 19, 2016 at 12:53

Ulf Gjerdingen

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2 Comments

Derekyy Over a year ago

No, printing those node only give me sthg like this: [<selenium.webdriver.remote.webelement.WebElement (session="fb86fb35-d2fa-974a-af32-a15db1b7459d", element="{c1dad34f-764d-0249-9302-215dd9ae9cd8}")>, <selenium.webdriver.remote.webelement.WebElement (session="fb86fb35-d2fa-974a-af32-a15db1b7459d", element="{a53816f4-9952-ab49-87ac-5d79538a855d}")>, ...]

Ulf Gjerdingen Over a year ago

do you use the loop for node in nodes: ?

Robert Longson · Accepted Answer · 2016-08-19 13:08:44Z

2

find_elements_by_tag_name can be used to find path children.

Once you have those, get_attribute("d") will get you the path value.

E.g.

for node in nodes:
    paths = node.find_elements_by_tag_name("path")
    for path in paths:
        value = path.get_attribute("d")

answered Aug 19, 2016 at 13:08

Robert Longson

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2 Comments

Derekyy Over a year ago

thx a lot, it works. only have to change this line: paths = driver.find_elements_by_tag_name("path") thx everyone's effort

Robert Longson Over a year ago

That will find you all the paths whether or not they are children of g elements.

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