Finding a part of string in an array of strings

Question

Iv been looking for a way to search through an array of strings and find if there are any strings that contain a part of another string, if there is then i merge the whole array onto another array. EG:

Searching for jav:
array->[java] -> would return this value
and add that whole array to another

After looking around on stackoverflow and testing i found this solution using strpos which works...kind of:

$matches=array(); //just here to show the array is declared and is filled with items prior to calling 

foreach($myarray as $fn){
    if(strpos($fn,$searchString)){
        $matches = array_merge($myarray,$matches);
    }
    }

The issue is, instead of adding the whole array its adding my search string each loop however, after double checking a number of times i dont understand why. Tts adding the original search item rather than the entire other array.... EG.

If i search for jav as shown above the array will merge to create an array of the correct length but with the value :

javjavjavjavjav

Any help in understanding exactly why this is or how to correct it would be appreciated.

what does $myarray contain? example, is this just a simple flat array? — Kevin
– Kevin, Commented Aug 23, 2016 at 23:30
My array contains a list of words such as java,csharp,c++ etc so I expected the match of jav to java to results it in merging the array to the other array but instead it merges the search string the correct number of times.. — D3181
– D3181, Commented Aug 23, 2016 at 23:32

Juan.Queiroz · Accepted Answer · 2016-08-23 23:33:57Z

1

The function strpos return false or 0, so the array matches will not save any word with text jav.

This is my solution:

$myarray = ['java', 'java3', 'mouse', 'java2', 'keyboard'];
$matches = [];
foreach ($myarray as $fn) {
    if (strpos($fn, 'jav') !== false) {
        $matches[] = $fn;
    }
}

PS: I don't know if i understood correctly your question, but i hope.

answered Aug 23, 2016 at 23:33

Juan.Queiroz

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