angular.copy() returning Object when source is Array

Question

I want to create a copy of my arguments inside a logging function using angular.copy().

Since the arguments is already an Array, I expected to get an Array but it returned Object instead of Array.

$scope.log = function(argN) {
    console.log("arguments", arguments, angular.copy(arguments));
    if (typeof(console) !== 'undefined') {
        console.log.apply(console, angular.copy(arguments));
    }
}

Is this some sort of standard practice of copying?
How can I get Array instead of Object?

arguments is not an array.

Daniel A. White
– Daniel A. White

2016-09-06 17:32:30 +00:00
Commented Sep 6, 2016 at 17:32 — Daniel A. White
– Daniel A. White, Commented Sep 6, 2016 at 17:32

Daniel A. White · Accepted Answer · 2016-09-06 17:41:34Z

2

arguments is not an array but array like. To do a shallow clone of arguments, use Array.prototype.slice.call(arguments). That will create an array of all the arguments. From there, to get a deep clone, use angular.copy.

var foo = angular.module('foo', []);

foo.controller('bar', function($scope) {
   $scope.trace = function() {
       var clonedArguments = angular.copy(arguments);
       console.log(clonedArguments);
       var clonedArgs = angular.copy(Array.prototype.slice.call(arguments));
       console.log(clonedArgs);
   };
  $scope.trace(1, 'foo', { bar: 27 })
});

<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div ng-app="foo" ng-controller="bar"></div>

edited Sep 6, 2016 at 17:41

answered Sep 6, 2016 at 17:34

Daniel A. White

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Community · Accepted Answer · 2017-05-23 12:33:40Z

0

Edit: I think console.dir() maybe what you are looking for after reading this

Print JSON parsed object?

edited May 23, 2017 at 12:33

CommunityBot

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answered Sep 6, 2016 at 17:23

user3685048

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