php call nested function

Question

i wonder how php can achieve like below function design:

Class->func()->func()

Here is the laravel validate example.

    $validator->after(function($validator) 
    {
        if ($this->somethingElseIsInvalid()) 
        {
            **$validator->errors()->add('field', 'Something is wrong with this field!');**
        }
    });

Is the after() do the magic work here?

And how to create my own code that can behave like this.

In your methods you can do return $this; which returns the object and gives you the possibility to do class->func()->func()->func() — user1897253
– user1897253, Commented Sep 15, 2016 at 6:43
@Neat thanks and it's call method Chaining, learn somethings new today : ) — Tyler
– Tyler, Commented Sep 15, 2016 at 6:57

masterFly · Accepted Answer · 2016-09-15 08:35:13Z

5

Its called Method Chaining.

Method chaining works because a function or a method of the class always returns object which further call another function.

Basically it returns it self.

Ex:

public function method1() {
    // method content ...
    return $this;
}

public function method2() {
    // method content ...
    return $this;
}

Please refer the following link to read more on Method Chaining,

http://www.techflirt.com/tutorials/oop-in-php/php-method-chaining.html

There will be more articles you could find on this.

edited Sep 15, 2016 at 8:35

answered Sep 15, 2016 at 6:43

masterFly

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2 Comments

Limon Monte Over a year ago

While this link may answer the question, it is better to include the essential parts of the answer here and provide the link for reference. Link-only answers can become invalid if the linked page changes.

masterFly Over a year ago

@limonte, Thanks for the comment. I updated my answer. Your comments are most welcome!

Devon Bessemer · Accepted Answer · 2016-09-15 06:43:35Z

3

You need to return the object you want to chain the next method to.

public function chain() {
    return $this;
}

Sometimes this will be the current class ($this), somethings this will be an instance of another class depending on what is appropriate.

answered Sep 15, 2016 at 6:43

Devon Bessemer

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