How to take input as String with spaces in java using scanner

Question

I need to read spaces (present before string and after String) given as input using Scanner Note : if there is no spaces given in input it should not add space in output

Please find the below code:

package practise;

import java.util.Scanner;

public class scanccls {

    public static void main(String[] args) {
        // TODO Auto-generated method stub
        Scanner scan = new Scanner(System.in);
         String name= scan.nextLine();
        name+=scan.nextLine();
         scan.close();

        System.out.println("Enter your name"+name); 

    }

}

I am expecting output like:

Input :Enter Your name:Chandu Aakash
Output:chandu Aakash
Input: Enter Your name: (Space..)Chandu Aakash(Space..)
Output: (space.. )chandu Aakash(Space..)

JHDev · Accepted Answer · 2016-09-15 15:28:46Z

33

Your code work fine. I just add little modification:

package practise;

import java.util.Scanner;

public class scanccls {

    public static void main(String[] args) {

        System.out.println("Enter your name:"); 
        Scanner scan = new Scanner(System.in);
        String name="";

        name+=scan.nextLine();
        scan.close();

        System.out.println("Your name is :"+name); 

    }

}

answered Sep 15, 2016 at 15:28

JHDev

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Comments

Rajesh · Accepted Answer · 2018-10-03 07:05:27Z

25

One can use the delimiter function to segregate your input as shown below.

import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in).useDelimiter("\n");
        String input = scanner.next();
        System.out.println(input);
        scanner.close();

    }
}

answered Oct 3, 2018 at 7:05

Rajesh

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Comments

Anam · Accepted Answer · 2018-11-04 15:48:00Z

14

import java.util.*;
public class Str{
    public static void main(String[] args) throws IOException
    {
        Scanner scan = new Scanner(System.in);
        int i = scan.nextInt();
        double d = scan.nextDouble();
        String s=" ";
        s= scan.nextLine();
        s+=scan.nextLine();
        scan.close();

        System.out.println("String: "+s);
        System.out.println("Double: "+d);
        System.out.println("Int: "+i);
    }
}

answered Nov 4, 2018 at 15:48

Anam

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4 Comments

uudaddy Over a year ago

The solution above worked for a HackerRank exercise: hackerrank.com/challenges/java-stdin-stdout/… (HackerRank editor has some limitation on regular expression, btw. The above solution is the best approach I can find)

Ash Jul 16 at 16:09

Can you explain how does this works? I was trying the hackrrank challenge also. I didnt understand why it works

uudaddy Jul 30 at 21:21

It's reading in the int, the double, and then the string sequentially. Then output them.

Ash Aug 5 at 16:35

How is the string with spaces is being read? Why we are doing sc.nextLine twice? Shoudnt one would suffice. Also why we have initiliazed s with " "

Arvind Bakshi · Accepted Answer · 2020-02-13 06:46:26Z

3

/@esprittn solution didn't work./

my solution:

while(scan.hasNext()){
name+=scan.nextLine();
}

answered Feb 13, 2020 at 6:46

Arvind Bakshi

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Comments

Rezza Prayogi · Accepted Answer · 2018-12-18 08:51:03Z

I use this function below, to read from all user input format, text inclusive spaces, then parse to specific datatype after.

package practice;
import java.io.*;

public class readInputSample{
   public static void main(String[] args) {
        String strVal = getInput("Enter string value: "); // Direct as string
        Integer intVal = Integer.parseInt(getInput("Enter integer value: "));
        Double dblVal = Double.parseDouble(getInput("Enter double value: "));
        Float fltVal = Float.parseFloat(getInput("Enter float value: "));

        System.out.println("String value: " + strVal);
        System.out.println("Integer value: " + intVal);
        System.out.println("Double value: " + dblVal);
        System.out.println("Float value: " + fltVal);
   }

   // Special Function to read all user input
   private static String getInput(String prompt){
      BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in));

      System.out.print(prompt);
      System.out.flush();

      try{
          return stdin.readLine();
      } catch (Exception e){
        return "Error: " + e.getMessage();
      }
    }
}

Anubhav Mishra · Accepted Answer · 2020-09-26 14:16:38Z

2

I have done a few changes in your code, it will run just fine for this code

package practise;

import java.util.Scanner;

public class scanccls {

    public static void main(String[] args) {
        //// TODO Auto-generated method stub

        System.out.println("Enter your name:"); 
        Scanner scan = new Scanner(System.in);
        String name="";

        name+=scan.nextLine();
        scan.close();

        System.out.println("Your name is :"+name); 

    }

}

answered Sep 26, 2020 at 14:16

Anubhav Mishra

1277 bronze badges

Comments

Lalji Dhameliya · Accepted Answer · 2019-06-04 07:05:09Z

0

package practise;
import java.util.Scanner;

public class scanccls
{
    public static void main(String[] args)
    {
        System.out.println("Enter your name:");
        Scanner scan = new Scanner(System.in);
        String name = "";
        name += scan.nextLine();

        // Can also be done like
        // String name=scan.next();
        // name+=scan.nextLine();

        // They Both Work as same

        System.out.println("Your name is :" + name);
    }
}

edited Jun 4, 2019 at 7:05

Lalji Dhameliya

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answered Jun 4, 2019 at 5:59

Vishal Bhola

1

Comments

Traian GEICU · Accepted Answer · 2022-03-07 17:49:40Z

0

package practise;
import java.util.Scanner;
public class scanccls {

public static void main(String[] args) {
    // TODO Auto-generated method stub
    Scanner scan = new Scanner(System.in);
    String name= scan.nextLine();
    scan.close();

    System.out.println("Enter your name"+name); 
}
}

edited Mar 7, 2022 at 17:49

Traian GEICU

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answered Mar 4, 2022 at 2:46

PravinMahandule

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