I have read a-lot of answers on this but they don't seem to be working.
I have the following code:
$amountoflikes=mysql_query("SELECT * FROM `uc_likes` WHERE `dwable` = '372'");
This returns the following:
If I wanted to echo the value of dwable in the 2nd row for instance (not involving the initial query).
I've tried:
while($row3 = mysql_fetch_assoc($amountoflikes)){
$json[] = $row3;
}
echo json_encode($json);
But this returns null.
I'm currently using PHP 5.5 (native).
I'm not using MySQLi or MySQL PDO.
Can someone tell me where I'm going wrong. Ideally I'd prefer not to use a loop but I don't know if that's possible.
Thanks!

echo $row3['dwable'];? If you are doing`dwable` = '372'why even execute the query you knowdwablewill be372.