How to return specific values in an array?

Question

Simply, I have a set of numbers like this.

int targetNumber = 8;

int[] n = new int[4];
n[0] = 2;
n[1] = 4;
n[2] = 8;
n[3] = 16;

Now, I'm trying to return 3 numbers.

For example, since n[2] is equal to the targetNumber, I want to return n[0], n[1], and n[3].

Any ways on how I can do that?

You can only return one object or primitive. You could, for example, return a smaller array with the values you want, or define an object with related fields then set those fields and return the object. — Zarwan
– Zarwan, Commented Oct 2, 2016 at 2:03

Dev. Joel · Accepted Answer · 2016-10-02 02:28:16Z

4

You can make use of the interface Stream

Arrays.stream(n)
.filter(value -> value != targetNumber)
.limit(3)/*if you want to print only the first three results*/
.forEach(System.out::println);

answered Oct 2, 2016 at 2:28

Dev. Joel

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1 Comment

Kcits970 Over a year ago

Thanks, I recently started learning about Java streams, and this answer is very helpful for me.

Maytham Fahmi · Accepted Answer · 2016-10-02 02:42:50Z

2

You can do it in classic fashion:

for (int i : n) {
    if (i != targetNumber)
        System.out.println(i);
}

output will be n[0], n[1] and n[3]

2
4
16

answered Oct 2, 2016 at 2:42

Maytham Fahmi

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4 Comments

Dev. Joel Over a year ago

I thought the question was getting only three numbers :)

Maytham Fahmi Over a year ago

@Dev.Joel your answer is valid I think it might be over complicated for OP, I like streams but maybe OP have not enough knowledge of streams yet. any way I give my vote for you as well. I think also he mean 3 remain numbers of 4

Dev. Joel Over a year ago

It is also possible that the focus of the question is to return 3 items because the array is 4. I understood back 3 items generally equal his response was accepted because it was what he wanted the OP. all right

Maytham Fahmi Over a year ago

I agree but I think still the only reason OP did not get it because it is new stuff to him/her to understand any nice chatting with you.

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