Python: How to initialize a list with generator function

Question

Let's say i have 2 following functions:

def get_items():
    items = []
    for i in xrange(2, 10):
        items.append(i)
    return items

def gen_items():
    for i in xrange(2, 10):
        yield i

I know i can use both of them in a for loop like this

for item in gen_items():
    do something

But now i need to initialize a variable as list, like this

mylist = get_items()

but with the generator function. Is there a way to do it without a for loop appending the items from generator?

xrange returns an object which is lazy evaluated in Python 2 like the range function in Python 3. So if all your generator function is doing is iterate over the xrange object, then list(xrange(2, 10)) will work beautifully. — Sede
– Sede, Commented Oct 6, 2016 at 14:33
@Farhan.K: I know, it was just example to explain my question, i don't really have any such function on my code. — Youda008
– Youda008, Commented Oct 6, 2016 at 14:48

Tim D · Accepted Answer · 2016-10-06 14:22:05Z

4

The list builtin will accept any iterator:

l = list(gen_items())

answered Oct 6, 2016 at 14:22

Tim D

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Cory Kramer · Accepted Answer · 2016-10-06 14:22:14Z

3

You can just directly create it using list which will handle iterating for you

>>> list(gen_items())
[2, 3, 4, 5, 6, 7, 8, 9]

answered Oct 6, 2016 at 14:22

Cory Kramer

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