PHP - Calling class functions from outside the class returns undefined function error

Question

So I have a class and I created an object of the class outside of it. When I try to execute the function createSummonerBasicArray() I get this error "Fatal error: Call to undefined function prepSummonerBasic()". So apparently it is saying prepSummonerBasic() does not exist. I tried making both functions public and it didn't change the error. New to PHP btw.

Class SummonerSearch{

    function prepSummonerBasic($summoner, $server) {

    }

    function createSummonerBasicArray($summoner, $server){
        $summonerBasic = prepSummonerBasic($summoner, $server);
    }

};

$obj = new SummonerSearch('crippy', 'na');
$obj->createSummonerBasicArray('crippy','na');

Have you tried $this->prepSummonerBasic(...) ?

BlitZ
– BlitZ

2016-10-14 04:14:13 +00:00
Commented Oct 14, 2016 at 4:14 — BlitZ
– BlitZ, Commented Oct 14, 2016 at 4:14
I didn't but that was the solution.

SheepBandit
– SheepBandit

2016-10-14 04:18:52 +00:00
Commented Oct 14, 2016 at 4:18 — SheepBandit
– SheepBandit, Commented Oct 14, 2016 at 4:18

Fu Xu · Accepted Answer · 2016-10-14 04:14:51Z

3

function createSummonerBasicArray($summoner, $server){
    $summonerBasic = $this->prepSummonerBasic($summoner, $server);
}

you must call it with $this->, not like in java

answered Oct 14, 2016 at 4:14

Fu Xu

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1 Comment

SheepBandit Over a year ago

Thanks for the fast reply! That worked but can you explain a little about why $this-> is necessary?

Razib Al Mamun · Accepted Answer · 2016-10-14 05:18:42Z

0

Try this with used static keyword:

<?php
Class SummonerSearch{
    public static function prepSummonerBasic($summoner, $server) {
        echo $summoner;
    }

    function createSummonerBasicArray($summoner, $server){
        $summonerBasic = self::prepSummonerBasic($summoner, $server);
    }
};

$obj = new SummonerSearch('crippy', 'na');
$obj->createSummonerBasicArray('crippy','na');
?>

answered Oct 14, 2016 at 5:18

Razib Al Mamun

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