How to create variables using a php array?

Question

I have a PHP array, something like below:

Array(

  [0] => Array
      (
          [name] => month_year
          [value] => 201609
      )

  [1] => Array
      (
          [name] => advance_amount
          [value] => 50%
      )

)

Using this array, I want to create 2 variables like this:

$month_year = '201609'; 
$advance_amount = '50%';

Can anybody tell me is this possible in php?

I tried it using two foreach but I don't have any idea how to precced.

foreach ($_POST as $k => $data) {
  //echo "<pre>", print_r($data)."</pre>";
  foreach ($data as $key => $value) {
    echo $key."<br>";
  }
}

Rajdeep Paul · Accepted Answer · 2016-10-16 13:42:24Z

2

Use variable variables. Your foreach loop should be like this:

foreach ($_POST as $k => $data) {
    $$data['name'] = $data['value'];
}

// display variables
echo $month_year . "<br />";
echo $advance_amount;

answered Oct 16, 2016 at 13:42

Rajdeep Paul

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Comments

jakub wrona · Accepted Answer · 2016-10-16 13:45:48Z

1

PHP7 style:

$a = [['name' = 'month_year', 'value' => '201609'], ['name' => 'advance_amount', 'value' => '50%']];


foreach ($a as $line) {
    ${$line['name']} = $line['value'];
}

php > echo $month_year; //201609

Have a look at the Variables reference

Caution

Further dereferencing a variable property that is an array has different semantics between PHP 5 and PHP 7. The PHP 7.0 migration guide includes further details on the types of expressions that have changed, and how to place curly braces to avoid ambiguity.

answered Oct 16, 2016 at 13:45

jakub wrona

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Comments

Jorge Y. C. Rodriguez · Accepted Answer · 2016-10-16 13:59:20Z

1

using list it gives you the cleaner way to solve the issue: for example

$data = [
    [
        'name' => 'month_year',
        'value' => 201609
    ],
    [
        'name' => 'advance_amount',
        'value' => '50%'
    ]
];

list($month_year, $advance_amount) = array_map(function($value){
    return $value['value'];
}, $data);

echo sprintf('Month of the year is %s with porcentage %s', $month_year, $advance_amount);

This will have the result you are looking for with a clearer code.

Month of the year is 201609 with porcentage 50%

answered Oct 16, 2016 at 13:59

Jorge Y. C. Rodriguez

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Comments

Nadim Sheikh · Accepted Answer · 2016-10-16 13:52:25Z

0

first create loop and declare var.

  $data = array(array(
            'name' => 'month_year',
            'value' => 201609,
        ), array(
            'name' => 'advance_amount',
            'value' => '50%',
        )
    );

    foreach ($data as $key => $value) {
        ${$value['name']} = $value['value'];
    }


    echo $month_year;
    echo '<br>';
    echo $advance_amount;

answered Oct 16, 2016 at 13:52

Nadim Sheikh

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