I have a problem, I don't understand why arr.slice doesn't work when the first value is 0, the returned array is empty:
function chunkArrayInGroups(arr, size) {
var newArr = [];
for (var i = 0; arr[i]; i += size) {
newArr.push(arr.slice(i, i + size));
}
return newArr;
}
console.log(chunkArrayInGroups([0, 1, 2, 3, 4, 5, 6], 3));You end direct the loop with the condition, which evaluates as false.
arr[i] -> arr[0] -> 0 -> false -> end for loop
Use the length of the array as check
for (var i = 0; i < arr.length; i += size) {
// ^^^^^^^^^^^^^^
function chunkArrayInGroups(arr, size) {
var newArr = [];
for (var i = 0; i < arr.length; i += size) {
newArr.push(arr.slice(i, i + size));
}
return newArr;
}
console.log(chunkArrayInGroups([0, 1, 2, 3, 4, 5, 6], 3));try with this
function chunkArrayInGroups(arr, size) {
// Break it up.
var newArr = [];
for (var i = 0; typeof arr[i]!='undefined'; i += size) {
newArr.push(arr.slice(i, i + size));
}
return newArr;
}
chunkArrayInGroups([0, 1, 2, 3, 4, 5, 6], 3)
The problem is arr[i] not arr.slice.
First Element of [0, 1, 2, 3, 4, 5 ,6] is 0 and it is false.
Just use other conditions like i < arr.length in for statement.
for (var i = 0; arr[i]; i += size) , arr[0] is 0, means false, so the loop is never entered
for (var i = 0; arr[i]; i += size) {?