Javascript: Filter out on an array of objects and pick based on key, not value

Question

Im trying to loop through an array of objects, which have different keys. Is there a way that I can pick an object based on they key?

var array = [
  {
    "1400": "Accident and Health"
  },
  {
    "100": "Life"
  },
  {
    "1300": "Pension"
  }
]
var a = "100";
var pop = _.pick(array,a);
console.log(pop);

Desired output:

Life

Thank you!

Nina Scholz · Accepted Answer · 2016-11-20 17:39:16Z

3

You could use the in operator.

var array = [{ 1400: "Accident and Health" }, { 100: "Life" }, { 1300: "Pension" }];

var result = (key => array.find(item => key in item)[key])(100);

console.log(result);

answered Nov 20, 2016 at 17:39

Nina Scholz

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Comments

Mahi · Accepted Answer · 2016-11-20 17:40:17Z

0

var array = [
  {
    "1400": "Accident and Health"
  },
  {
    "100": "Life"
  },
  {
    "1300": "Pension"
  }
]
var a = "100";


var pop = _.map(array, function(currentObject) {
  var b= _.pick(currentObject, a);
  if(!_.isEmpty(b))
    console.log(b);
});

<script src="http://underscorejs.org/underscore-min.js"></script>

answered Nov 20, 2016 at 17:40

Mahi

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Comments

stasovlas · Accepted Answer · 2016-11-20 18:46:27Z

0

Lodash 4.17.2

_.chain(array).map('100').compact().head().value();

answered Nov 20, 2016 at 18:46

stasovlas

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