//c++ funciton definition
int LS_SomeFucntion(LuaState* state)
{
LuaStack args(state);
//..
set<int>::iterator it = mySet.begin();
for(; it != mySet.end(); ++it)
{
state.pushInteger(*it);
}
return mySet.size();
}
state->GetGlobals().Register("SomeFunction",LS_SomeFunction);
//lua scripts
??? = SomeFunction()
How to get the return value of SomeFunction() in lua scripts when the size is not know when the function is called?
You can capture all the return values in a table:
local rv = { SomeFunction() }
print('SomeFunction returned', #rv, 'values')
for i,val in ipairs(rv) do
print(i,val)
Or process them using a variable parameter list:
function DoSomething(...)
local nargs = select('#', ...)
print('Received', nargs, 'arguments')
for i=1,nargs do
print(i,select(i,...))
end
DoSomething(SomeFunction())
Of course, your C function should probably just return a Lua table containing the list items. I'm not familiar with the LuaPlus, but judging from the documentation here, you'd want something like this:
int LS_SomeFunction(LuaState* state)
{
LuaObject table;
table.AssignNewTable(state, mySet.size()); // presize the array portion
int i = 1;
for(set<int>::iterator it = mySet.begin(); it != mySet.end(); ++it)
table.SetNumber(i++, *it);
table.PushStack();
return 1;
}
Then you just say:
local rv = SomeFunction()
print('SomeFunction returned', #rv, 'values')
