Sorting floating Pointer array [duplicate]

Question

We have:

 private void function(ptr* data, const int size_of_data){
       std::sort(std::begin(data), std::end(data), floatcomparer);

Is this actually possible? Is there another way? Cause I get here an error: no instance of overloaded function ""std::begin" matches the argument types are: (float *). I know that we need the size for a fast sorting algorithm like std uses and ptr* doesn't deliver an included size. But shouldn’t there be a way cause I know how big the array is I'm pointing on?

Neither is private. Please read en.cppreference.com/w/cpp/language/access — pSoLT
– pSoLT, Commented Dec 29, 2016 at 11:08
You can if you pass an array by reference to function template. — user1593881
– user1593881, Commented Dec 29, 2016 at 11:37

Paul Evans · Accepted Answer · 2016-12-29 11:12:43Z

1

Your function signature is wrong and you're calling std::sort incorrectly, you want something more like:

void function(float* data, std::size_t size_of_data) {
    std::sort(data, data + size_of_size, std::less<float>());
}

answered Dec 29, 2016 at 11:12

Paul Evans

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talonmies · Accepted Answer · 2017-01-01 11:45:31Z

1

std::sort(arr, arr+ size, std::greater<float>());

where you can use pass float arr in this form

func(float[],int sz){...}

With this comparator you can sort it.

edited Jan 1, 2017 at 11:45

talonmies

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answered Dec 29, 2016 at 11:10

user2736738

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