I have below as string
name : abc,
position : 2
I want to make replace so that the string becomes as below
name : "abc",
position : 2
What change I want to do is abc will have double quotes so abc becomes "abc".
Note: abc is dynamic, it can be anything as below.
name : Test,
position : 2
name : Great,
position : 2
name : developers,
position : 2
Any idea how this can be done?
I suggest using \\b(name\\s*:\\s*)(.+), pattern and replace with $1"$2",:
NSError *error = nil;
NSString *myText = @"name : abc,\nposition : 2";
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@"\\b(name\\s*:\\s*)(.+)," options:nil error:&error];
NSString *modifiedString = [regex stringByReplacingMatchesInString:myText options:0 range:NSMakeRange(0, [myText length]) withTemplate:@"$1\"$2\","];
NSLog(@"%@", modifiedString);
See the Objective-C demo
Details:
\\b - a leading word boundary(name\\s*:\\s*) - Group 1 matching name, 0+ whitespaces, : and 0+ whitespaces again(.+) - any 0+ chars other than line break chars as many as possible, - commaThe replacement pattern - $1"$2", - inserts Group 1 contents, ", Group 2 contents and ",.
See the regex demo.
\t\tThis is test \t\tname : abc,\nposition : 2\n\nname : xyz,\nposition : 3\n\nname : jkl,\nposition : 3. Can you please look into this?
(?m)^ with \\b
name: and there may be optional whitespaces before a ,, yes, it will be better. .+ just matches the whole rest of the line. You might also want to check if \\b(name\\s*:\\s*)(.*\\S)\\s*, works "better" if there can be literally anything (but at least 1 non-whitespace) up to optional whitespace and ,. Mind that \s matches a newline, so, if you want to stay within 1 line, replace \\s with [\\p{Zs}\t] or [^\\S\r\n].
Anything can be anything?great, test, developershere they must be an object?