I am having string of four hex numbers like:
"0x00 0x01 0x13 0x00"
which is equivalent to 0x00011300. How i can convert this hex value to integer?
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Possible duplicate of How to get hex string from signed integerDanieboy– Danieboy2017-01-31 14:15:31 +00:00Commented Jan 31, 2017 at 14:15
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3 Answers
Since you are having string of hex values. You may remove ' 0x' from the string to get the single hex number string. For example:
my_str = "0x00 0x01 0x13 0x00"
hex_str = my_str.replace(' 0x', '')
where value hold by hex_str will be:
'0x00011300' # `hex` string
Now you may convert hex string to int as:
>>> int(hex_str, 16)
70400
answered Jan 31, 2017 at 14:19
Moinuddin Quadri
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Comments
>>> s="0x00 0x01 0x13 0x00"
>>> a=0
>>> for b in s.split():
... a = a*256 + int(b,16)
...
>>> a
70400
>>> hex(a)
'0x11300'
Comments
The answer is here Convert hex string to int in Python.
Without the 0x prefix, you need to specify the base explicitly, otherwise there's no way to tell:
x = int("deadbeef", 16)
With the 0x prefix, Python can distinguish hex and decimal automatically.
print int("0xdeadbeef", 0)
3735928559
print int("10", 0)
10
(You must specify 0 as the base in order to invoke this prefix-guessing behavior; omitting the second parameter means to assume base-10. See the comments for more details.)
