how to using variables in search pattern in awk script

Question

I want to print the pid when finding matched process while the match pattern is inputted:

ps aux | awk -v in="$1" '/in/{print $1}'

It seems the former awk sentence is not right. After checking many results in google like this, I change my script in the following but still cannot work:

ps aux | awk -v in="$1" '/$0 ~ in/{print $1}'

or

ps aux | awk -v in="$1" '($0 ~ in) {print $1}'

I think pgrep "$1" would be better option...

Sundeep
– Sundeep

2017-02-09 09:04:17 +00:00
Commented Feb 9, 2017 at 9:04 — Sundeep
– Sundeep, Commented Feb 9, 2017 at 9:04

anubhava · Accepted Answer · 2017-02-09 08:14:32Z

3

You are fairly close in all your attempts. Problem is that in is a reserved keyword in awk.

You can use:

ps aux | awk -v var="$1" '$0 ~ var {print $1}'

Or else non-regex way:

ps aux | awk -v var="$1" 'index($0, var) {print $1}'

answered Feb 9, 2017 at 8:14

anubhava

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